If the length of an arc is 12 inches and the radius of the circle is 10 inches, what is the measure of the arc? 216 degrees 270 degrees 288 degrees

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If the length of an arc is 12 inches and the radius of the circle is 10 inches, what is the measure of the arc? 216 degrees 270 degrees 288 degrees

Mathematics
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@campbell_st whered that answer go?
do you still need help?
yes please...

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Other answers:

ok
so, the first thing you need is the formula for arc length, which is \[arclength = 2piR(\frac{ \theta }{ 360 })\]
now, look at the values you are given
you have the arc length and the radius, so plug those in.
and what do you get when you do that?
where am i plugging the arc length into?
look at the formula, see where it says arc length? you plug the value you have for arc length right there.
yeah and i can plug in the radius too. but what am i solving for?|dw:1438157454848:dw|
yep! now you want to solve for theta.
theta?
so to make it easier, replace theta with x. it is the symbol in the numerator of the fraction: \[\theta\]
oh okay.
so the first step is to isolate x, the best way to do that is to first deal with everything outside the parenthesis
you know all the values for those, just solve 2πr
and then, what you want to do is divide both sides by the value that you get for 2πr, which will isolate the fraction and let you solve that next
62.8?
yep!
now divide both sides by 62.8
what do you get?
okay |dw:1438157770787:dw| now divide by it?
mhm, so it would be 12 over 62.8
that leaves you with \[\frac{ 12 }{ 62.8 } = \frac{ x }{ 360 }\]
now, go ahead and divide 12 by 62.8, what does that get you?
couldnt you do that as a proportion?
yes, you could if you like
seems easier
|dw:1438157995138:dw|
yep! so that would be the answer i believe.
isnt right
hmm, let me see if i did something wrong
yeah man
hmm, im not sure what I did Wrong, sorry :(
|dw:1438158390561:dw|
actually there is a dupe question and that also led to a dead end http://openstudy.com/study#/updates/52eafc6ae4b0d95ca6b32d90
hmm, could be the question then? idk if you looked at the work usuki, is it right?
its supposed to be 12 pi and copy paste takes out the pi part
I think the question is a bit screwed up... yes ! 12 pi that's what we need
there we go! lol
ok so then, it is 12π and not 12?
yep
alright, do you need help still then or are you good?
so its 216?
I don't know if I should touch on this.. if there's a duplicate question. why not look at the past and learn in the future?
good point, i didnt look :p
yes it is 216
I could go over it for verification purposes so given radius at 10 ( r = 10) Arc length is 12pi (s=12pi) we need theta \[s = \theta r \rightarrow \frac{s}{r} = \theta \] \[\frac{12 \pi}{10} = \theta \] that bad boy is in radians and we need degrees so multiply that 12pi/10 with 180/pi so the pi's cancel \[\frac{12 \pi}{10} \cdot \frac{180}{\pi} = \theta \] \[\frac{12 }{10} \cdot \frac{180}{1} = \theta \] \[\frac{2160}{10} = \theta \] \[216 = \theta \]
what would be the symbol/variable for arc length?
arc length is s radius is r angle is the theta
Alright, well thanks for the Help @UsukiDoll , ill be more careful in the future. goodnight!

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