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anonymous
 one year ago
If the length of an arc is 12 inches and the radius of the circle is 10 inches, what is the measure of the arc?
216 degrees
270 degrees
288 degrees
anonymous
 one year ago
If the length of an arc is 12 inches and the radius of the circle is 10 inches, what is the measure of the arc? 216 degrees 270 degrees 288 degrees

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@campbell_st whered that answer go?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you still need help?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so, the first thing you need is the formula for arc length, which is \[arclength = 2piR(\frac{ \theta }{ 360 })\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now, look at the values you are given

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you have the arc length and the radius, so plug those in.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and what do you get when you do that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0where am i plugging the arc length into?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0look at the formula, see where it says arc length? you plug the value you have for arc length right there.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah and i can plug in the radius too. but what am i solving for?dw:1438157454848:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yep! now you want to solve for theta.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so to make it easier, replace theta with x. it is the symbol in the numerator of the fraction: \[\theta\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the first step is to isolate x, the best way to do that is to first deal with everything outside the parenthesis

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you know all the values for those, just solve 2πr

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and then, what you want to do is divide both sides by the value that you get for 2πr, which will isolate the fraction and let you solve that next

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now divide both sides by 62.8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay dw:1438157770787:dw now divide by it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0mhm, so it would be 12 over 62.8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that leaves you with \[\frac{ 12 }{ 62.8 } = \frac{ x }{ 360 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now, go ahead and divide 12 by 62.8, what does that get you?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0couldnt you do that as a proportion?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, you could if you like

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438157995138:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yep! so that would be the answer i believe.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmm, let me see if i did something wrong

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmm, im not sure what I did Wrong, sorry :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438158390561:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3actually there is a dupe question and that also led to a dead end http://openstudy.com/study#/updates/52eafc6ae4b0d95ca6b32d90

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmm, could be the question then? idk if you looked at the work usuki, is it right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its supposed to be 12 pi and copy paste takes out the pi part

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3I think the question is a bit screwed up... yes ! 12 pi that's what we need

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so then, it is 12π and not 12?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3because that's also a dupe question http://openstudy.com/study#/updates/4e2c15f60b8b3d38d3ba2d2d

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alright, do you need help still then or are you good?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3I don't know if I should touch on this.. if there's a duplicate question. why not look at the past and learn in the future?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0good point, i didnt look :p

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3I could go over it for verification purposes so given radius at 10 ( r = 10) Arc length is 12pi (s=12pi) we need theta \[s = \theta r \rightarrow \frac{s}{r} = \theta \] \[\frac{12 \pi}{10} = \theta \] that bad boy is in radians and we need degrees so multiply that 12pi/10 with 180/pi so the pi's cancel \[\frac{12 \pi}{10} \cdot \frac{180}{\pi} = \theta \] \[\frac{12 }{10} \cdot \frac{180}{1} = \theta \] \[\frac{2160}{10} = \theta \] \[216 = \theta \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what would be the symbol/variable for arc length?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.3arc length is s radius is r angle is the theta

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright, well thanks for the Help @UsukiDoll , ill be more careful in the future. goodnight!
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