A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
MEDALS AND FAN
How do i slove this;
anonymous
 one year ago
MEDALS AND FAN How do i slove this;

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[2\pi =2pi r \left(\begin{matrix}30 \\360\end{matrix}\right) \]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0could you provide a screenshot of this? this just looks weird. O_O

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0and what are we solving for? for r? for ???

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is the radius of a circle in which a 30° arc is 2pi inches long? 24 inches 12 inches 2√3 inches

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0that's a bit better. looking for the radius of the circle..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0a 30 deg arc is 1/12 of a circle (since there are 360 deg in a circle) thus the circumference of this circle is 12x2 pi = 24 pi the circumference of a circle = 2 pi R, so we know that 2 pi R = 24 pi or R=12

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0oh yeah the circumference formula \[C = 2 \pi r\] \[\frac{C}{2\pi} = r\] a full circle is 360 degrees and we are given 30 degrees as the arc so \[\frac{360}{30} = 12\] so 12 must be r \[C = 2 \pi (12) =24 \pi\] so to check that \[\frac{24 \pi}{2\pi} = r\] \[12=r \] (my explanation is a bit messed up... I haven't done this in years )
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.