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ParthKohli
 one year ago
@dan815 @Kainui @ganeshie8 @Astrophysics Help me regain my creativity!
ParthKohli
 one year ago
@dan815 @Kainui @ganeshie8 @Astrophysics Help me regain my creativity!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0try practicing art like painting or drawing

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0Reciting a question from my memory: \(ABC\) is a triangle and it's given that \(b>c\). \(AD\) is an altitude and is given to be equal to \(\dfrac{abc}{b^2  c^2}\). If \(C = 23^{\circ} \) then find angle \(B\).

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438169365378:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2dw:1438169558232:dw

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0\[c \sin B = \frac{abc}{b^2  c^2}\]\[\sin B = \frac{bc}{b^2  c^2}\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2Oh you re looking for numerical value of angle B is it

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2dw:1438169798797:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2thats just sine law anyways

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2b > c implies B > 23

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.0Yeah Ik, did you get the numerical value?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2no, still clueless..

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2how this \[\frac{abc}{b^2c^2}=b\sin{c}\] gives this \[\sin{A}=\sin^2{B}\sin^2{C}\] ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2I mean how this \[\frac{abc}{b^2c^2}=b\sin{\color{red}{C}}\] gives this \[\sin{A}=\sin^2{B}\sin^2{C}\] ?

amilapsn
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{a}{\sin{A}}=\frac{b}{\sin{B}}=\frac{c}{\sin{C}}=k\]

amilapsn
 one year ago
Best ResponseYou've already chosen the best response.2\[\therefore a=k\sin{A},b=k\sin{B},c=k\sin{C}\]

amilapsn
 one year ago
Best ResponseYou've already chosen the best response.2\[\therefore \frac{abc}{b^2c^2}=b\sin{C}\Rightarrow \sin{A}=\sin^2{B}\sin^2{C}\]

amilapsn
 one year ago
Best ResponseYou've already chosen the best response.2\[\Rightarrow \sin{(BC)}=1\Rightarrow B=113^0\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2how \(\sin A = \sin^2B\sin^2C\) becomes \(\sin(BC) = 1\) ?

amilapsn
 one year ago
Best ResponseYou've already chosen the best response.2\[\sin{A}=\sin^2{B}\sin^2{C}=(\frac{1\cos{2B}}{2})(\frac{1cos2C}{2})\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2\[\begin{align}\sin{A}=\sin^2{B}\sin^2{C}&=(\frac{1\cos{2B}}{2})(\frac{1cos2C}{2})\\~\\ &=\frac{1}{2}(\cos 2C  \cos 2B)\\~\\ &= \sin(C+B)\sin(CB)\\~\\ &=\sin(A)\sin(CB)\\~\\ \end{align}\] \(\implies \sin(BC)=1=\sin(90) \implies B = C+90 = 113\) Awesome!

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2I did nothing, pls medal amila :)

amilapsn
 one year ago
Best ResponseYou've already chosen the best response.2\[\Huge\unicode{x1f63a}\]
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