## anonymous one year ago 3tan^2 (x) -1=0 the solutions of this equation over interval (0, ii) are

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1. LynFran

$3\tan ^{2}x-1=0$$(\sqrt{3}tanx-1)(\sqrt{3}tanx+1)=0$$\sqrt{3}tanx-1=0$$\sqrt{3}tanx=1$$tanx=\frac{ 1 }{ \sqrt{3} }$$x=\tan^{-1} \frac{ 1 }{ \sqrt{3} }+ n \pi$and $\sqrt{3}tanx+1=0$$\sqrt{3}tanx=-1$$tanx=\frac{ -1 }{ \sqrt{3} }$$x=\tan^{-1} \frac{ -1 }{ \sqrt{3} }+n \pi$