anonymous
  • anonymous
Fan for answer! The table below represents a linear function f(x) and the equation represents a function g(x): x f(x) −1 −5 0 −1 1 3 g(x) g(x) = 4x + 3 Part A: Write a sentence to compare the slope of the two functions and show the steps you used to determine the slope of f(x) and g(x). (6 points) Part B: Which function has a greater y-intercept? Justify your answer. (4 points)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@saseal Can you help?
anonymous
  • anonymous
You know how to find the equation of f(x)?
anonymous
  • anonymous
Not really sorry... Is it m = y2 - y2 over x2 - x1 ?

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anonymous
  • anonymous
yes take 2 of the points and plug em into the formula \[m=\frac{ y _{2} - y _{1} }{ x _{2} - x _{1} }\]
anonymous
  • anonymous
What do you mean when you say two points?
anonymous
  • anonymous
Value of f(x) is your y
anonymous
  • anonymous
so you have 3 points of the line here (-1,-5) , (0,-1) ,(1,3)
anonymous
  • anonymous
Oh I understand what you are saying thank you, so I just plug all those in function by function right?
anonymous
  • anonymous
yes
anonymous
  • anonymous
OK give me a min
anonymous
  • anonymous
you plug in the numbers into the formula for gradient
anonymous
  • anonymous
just choose any 2
anonymous
  • anonymous
Well I got one that is 0 - (-1) over -1 - (-5) that equals 4 would that be my slope?
anonymous
  • anonymous
yea so the line equation we have now is \[f(x) = 4x+c\]
anonymous
  • anonymous
now we can find the value of c by replace the value of f(x) and x
anonymous
  • anonymous
Oh ok thank you so much for your help do you need anything?
anonymous
  • anonymous
you got your answer?
anonymous
  • anonymous
Almost
anonymous
  • anonymous
c is the y-intercept of the line
anonymous
  • anonymous
It's given to you actually, look at x = 0 f(x) = -1
anonymous
  • anonymous
Because: \[4(0)+c=-1\]
anonymous
  • anonymous
ok ok
anonymous
  • anonymous
I get it sorry I was stuck you need anything?
anonymous
  • anonymous
Nah not really.
anonymous
  • anonymous
Well thanks for all the help!
anonymous
  • anonymous
You're welcome

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