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anonymous

  • one year ago

In how many ways can a committee consisting of 2 men and at least 2 women be chosen from 4 men and 3 women?

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  1. anonymous
    • one year ago
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    two men and at least 2 women means a) two men and two women b) two men and three women we can compute each

  2. anonymous
    • one year ago
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    2 men, 2 women \[\binom{4}{2}\times \binom{3}{2}\]i.e "four choose two times three choose two

  3. anonymous
    • one year ago
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    2 men, 3 women \[\binom{4}{2}\times \binom{3}{3}\] which is just \(\binom{4}{2}\) since three choose 3 is 1

  4. anonymous
    • one year ago
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    you know how to compute these?

  5. anonymous
    • one year ago
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    no

  6. anonymous
    • one year ago
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    have you seen "n choose k" sometimes written as \[_nC_k\] or \[\binom{n}{k}\]?

  7. anonymous
    • one year ago
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    yes

  8. anonymous
    • one year ago
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  9. anonymous
    • one year ago
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    Could you pls help me to get answers for those questions

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