anonymous
  • anonymous
Algebruh.
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
1.) Describe the direction of the parabola and determine the y-intercept and zeros of f(x) = 5x2 + 2x + 1 Find the vertex and the equation for the axis of symmetry of the parabola, showing your work, so Ray can include it in his coaster plan.
anonymous
  • anonymous
anonymous
  • anonymous
leading coefficient is positive ( it is 5 ) so it opens up

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anonymous
  • anonymous
So far I have The vertex is going straight down, it is an acute angle. The y-intercept is 1
anonymous
  • anonymous
the first coordinate of the vertex of \(y=ax^2+bx+c\) is \(-\frac{b}{2a}\) in your case it is \[-\frac{2}{2\times 5}=-\frac{1}{5}\]
anonymous
  • anonymous
that makes the axis of symmetry \[x=-\frac{1}{5}\]
anonymous
  • anonymous
the vertex is not an angle, acute or otherwise
anonymous
  • anonymous
the vertex is a point the first coordinate of that point is \(-\frac{1}{5}\)
anonymous
  • anonymous
the second coordinate of the vertex is what you get for \(y\) when you replace \(x\) by \(-\frac{1}{5}\)
anonymous
  • anonymous
I meant parabola.
anonymous
  • anonymous
Okay, here's what I have so far. 1.) Describe the direction of the parabola and determine the y-intercept and zeros of f(x) = 5x2 + 2x + 1 The parabola is going straight down, it is an acute angle, the y-intercept is 1.
anonymous
  • anonymous
I need to find the zeroes of f(x) = 5x2 + 2x + 1
anonymous
  • anonymous
anonymous
  • anonymous
welshfella
  • welshfella
well I can tell you there are no real zeroes to this

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