## anonymous one year ago Algebruh.

1. anonymous

1.) Describe the direction of the parabola and determine the y-intercept and zeros of f(x) = 5x2 + 2x + 1 Find the vertex and the equation for the axis of symmetry of the parabola, showing your work, so Ray can include it in his coaster plan.

2. anonymous

@satellite73 @sammixboo @Mertsj @NeonStrawsForever @ParthKohli @e.mccormick

3. anonymous

leading coefficient is positive ( it is 5 ) so it opens up

4. anonymous

So far I have The vertex is going straight down, it is an acute angle. The y-intercept is 1

5. anonymous

the first coordinate of the vertex of $$y=ax^2+bx+c$$ is $$-\frac{b}{2a}$$ in your case it is $-\frac{2}{2\times 5}=-\frac{1}{5}$

6. anonymous

that makes the axis of symmetry $x=-\frac{1}{5}$

7. anonymous

the vertex is not an angle, acute or otherwise

8. anonymous

the vertex is a point the first coordinate of that point is $$-\frac{1}{5}$$

9. anonymous

the second coordinate of the vertex is what you get for $$y$$ when you replace $$x$$ by $$-\frac{1}{5}$$

10. anonymous

I meant parabola.

11. anonymous

Okay, here's what I have so far. 1.) Describe the direction of the parabola and determine the y-intercept and zeros of f(x) = 5x2 + 2x + 1 The parabola is going straight down, it is an acute angle, the y-intercept is 1.

12. anonymous

I need to find the zeroes of f(x) = 5x2 + 2x + 1

13. anonymous

@satellite73 @sammixboo @Empty @welshfella

14. anonymous

@DarkMoonZ @DaBest21

15. welshfella

well I can tell you there are no real zeroes to this