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anonymous
 one year ago
I need to find the zeroes of f(x) = 5x2 + 2x + 1
anonymous
 one year ago
I need to find the zeroes of f(x) = 5x2 + 2x + 1

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@AliceCullen @ramseysa @Elsa213 @DaBest21 @thomaster

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1zeroes are just your solutions. It's where x=0, or where the graph crosses the xaxis. Do you know how to solve quadratics?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1Here, take a look at this tutorial to see if you understand. If you still need help, please do tag me and I'll try my best to help you! http://openstudy.com/users/bloomlocke367#/updates/55acffcee4b071e6530c96ce

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait, is 1/5 and 4/5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Are those the zeroes?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1Actually, I'm pretty sure the zeroes are complex roots. One moment. I have to double check my work.

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1No, those are not the roots. They are, in fact, complex. Do you know what a complex number is?

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1Basically, a complex number is a number that has an imaginary number in it. The often have a coefficient, i, and a constant. Here's an example of what it would look like: 3i+8. That's just an example, not the answer. Do you understand imaginary numbers? Where did you get those answers?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Mathway, I suck at math and despise it. I'm sorry, I'm a history and English guy.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Actually, I got them from Wolfram/Alpha

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1Really? huh. Try using the quadratic formula, which is \(\LARGE x=\frac{b\pm\sqrt{b^24ac}}{2a}\)

BloomLocke367
 one year ago
Best ResponseYou've already chosen the best response.1In this case, a is 5, b is 2, and c is 1.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(2±√(2^24*5*1))/(2*5)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is it 1/10(2 ± 4i)?

radar
 one year ago
Best ResponseYou've already chosen the best response.0Actually you were right. You stated you had to find the 0"s of f(x) = 5x^2 + 2x + 1 This is the value where f(x) = 0. Obviously f(x) depends on x and x can be an infinite number of values both positive and negative and complex. When x = 0, in this given function f(x) = 1, when x = 1, f(x) = 4 etc. for f(x) = 0 you would solve for x, and the quadratic equation would be a reasonable method, however when you graph this function you will find that the f(x) nevers gets to 0. This does not mean that the function does not exists it simply means there is nor real "0" for f(x) for any real value of x.
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