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anonymous
  • anonymous
|dw:1438188392865:dw|
anonymous
  • anonymous
Is that right?
anonymous
  • anonymous
I read the question wrong

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anonymous
  • anonymous
I am not sure
anonymous
  • anonymous
I will tag someone
anonymous
  • anonymous
anonymous
  • anonymous
Thank you.
Nnesha
  • Nnesha
link is not working ..
Nnesha
  • Nnesha
http://prntscr.com/7ygsx9 thats what i got
anonymous
  • anonymous
It's not showing up.
anonymous
  • anonymous
Nnesha
  • Nnesha
is there a pic ?
anonymous
  • anonymous
No.
anonymous
  • anonymous
All I need is a simple yes or no.
Nnesha
  • Nnesha
what is this for http://prntscr.com/7ygv2z ?
welshfella
  • welshfella
i cant see it either
Nnesha
  • Nnesha
need more information
anonymous
  • anonymous
No I don't, it's perfectly fine.
Nnesha
  • Nnesha
WE need it......
anonymous
  • anonymous
Well I have no more information to provide you with.
anonymous
  • anonymous
@welshfella can you see?
Nnesha
  • Nnesha
I told you that the link u posted above is not working please post the link again so we can see it
anonymous
  • anonymous
Oh. The link I posted? I thought you meant yours.
Nnesha
  • Nnesha
http://prntscr.com/7yh2hl this one
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
There
Nnesha
  • Nnesha
thanks.
Nnesha
  • Nnesha
yep that's right.. use sin function \[\huge\rm sin (45) =\frac{ 16 }{ BC }\]
anonymous
  • anonymous
Thank you.

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