A community for students.
Here's the question you clicked on:
 0 viewing
Photon336
 one year ago
Questions (rate(s) and rate laws)
Enjoy
Photon336
 one year ago
Questions (rate(s) and rate laws) Enjoy

This Question is Closed

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2#1 I haven't still done the environmental chemistry at school. But I'll go with D none of the above!

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1#1 Graph I exothermic Graph II endothermic Agree/disagree?

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2oh sorry my answer goes to the second one !

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2that Ozone and NO reaction

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2for the exothermic endothermic question i'll go with C In an exothermic reaction the products are having less energy cuz in an exothermic reaction heat is lost to the surroundings !

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2the otherway round for the enothermic reaction.

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1One thing you notice is that NO remains unchanged

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1it's used in the first step of the reaction and then remains at the end of the reaction in the last step unchanged. so I would say that it's acting as a catalyst.

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1#2 A is definitely wrong because it does change the concentration of O3

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2so its gonna e B for the #2 question ?

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2259. I'll go with enthalpy change of the reaction

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1I think the issue is that NO is not present in the slow step so i thought it wouldn't cause any change. with that.

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1I think i'll go with C. catalyst only lowers activation energy but doesn't do anything else in terms of overall energy. that stay the same.

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1dw:1438191437577:dw the energy difference between products & reactants is the same

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2yeah I agree! that's what I was saying . and for the 260. is it the 3rd answer!

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1For #1 we are correct.

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1#2 i was between C and D and it was D. apparently NO does affect the overall energy change.

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1@Ciarán95 thoughts on #2?

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2Then that was the 1st answer I gave is correct? Okai now this is how I argued to take that answer. Rate determining step is determined by the slowest reaction out of all right?

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2There u can see that NO has no effect on it! Hence it says that even if we use NO as a catalyst its useless cuz it does not effect the rate determining step right?

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2Hence it won't lower the activation energy neither does it lower the overall energy !

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1overall rate of reaction is dependent on the rate determining step..

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2yes ! So I think that is the way to approach it ?

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1Thing is it does affect the overall energy choice C the one that says it doesn't is false.

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2The rate determining step is the slowest step . So if NO doesn't affect the rate of the slowest step that means it's useless as a catalyst cuz the rate of the reaction is not increased. if u want to increase the rate of the reaction u need to increase the rate of the slowest step. Since NO doesn't do that it doesn;t act as a catalyst.

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1so.. it technically doesn't act as a catalyst at all.. so it does affect the overall energy change making C false..

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1we still haven't done #3 (there's two questions for that)

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2for three 259. I have slight confusion with A and B But I would go for B

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1#3 our rate constant is \[r = k[A]^{x}[B]^{y}\] \[Lnk =Ae ^{Ea/RT}\] if we look at the bottom equation if we change the temperature we also change the value of K , b/c RT is in the denominator. a catalyst lowers the activation energy and thus increases the rate of the reaction. so that would affect K as well. Ea would be smaller and RT would remain unchanged. so for this one I would say it's B. Rate constant is independent of the enthalpy change.

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1any thoughts on #260 #3?

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2yey ! so it is the 2nd answer!

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2I though it would be that

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2for carbonates to release CO2 at a higher rate the concentrations of the acids should be high so we can eliminate A and B I choose C over D cuz they say the concentration of H is is directly connected to the rate.

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2the no. of H in C is greater than in D so I choose C.

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2@Ciarán95 are we arguing right?

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1\[H _{2}SO _{4}\] That's polyprotic? maybe more H+ So it could react faster.

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1oh *** wait that's H\[H _{2}SO _{3}\] There are weak acids with the exception of HCL

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1@Rushwr said the answer was HCl

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1Because it's a strong acid.

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1I chose C too but i thought it was sulfuric acid

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2So they have said it as HCl?

Photon336
 one year ago
Best ResponseYou've already chosen the best response.1yeah because they said it' a strong acid so it will produce more H+

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.2okai then. But the concentration is small nah !
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.