anonymous
  • anonymous
Solve1 over 25 = 5x + 4.
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
@phi
anonymous
  • anonymous
|dw:1438191114060:dw|
phi
  • phi
is 25 a power of 5 ?

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anonymous
  • anonymous
yes 5^2
phi
  • phi
do you know that 1/a can be written a^(-1) ?
phi
  • phi
so if we let 5^2 be "a" for the moment 1/(5^2) = (5^2)^-1 \[ \frac{1}{5^2}= \left(5^2\right)^{-1} \] now use the rule \[ \left(a ^b\right)^c = a^{bc} \]
anonymous
  • anonymous
Ok!
anonymous
  • anonymous
-5=x
phi
  • phi
can you show the steps?
anonymous
  • anonymous
(5^2)^-1=5^x+4 -1=x+4
anonymous
  • anonymous
x=-5
anonymous
  • anonymous
oh! I meant -6
phi
  • phi
the left side is not correct. the rule up above says a "power to a power" ... multiply the powers you get 5^(-2) (and you really should know this: 5^(-2) is the same as 1/5^2 )
phi
  • phi
-2 = x + 4 and yes you get x= -6
anonymous
  • anonymous
Thanks :)
anonymous
  • anonymous
And I do know that, I just had a brain fart
phi
  • phi
yw

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