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anonymous

  • one year ago

Solve1 over 25 = 5x + 4.

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  1. anonymous
    • one year ago
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    @phi

  2. anonymous
    • one year ago
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    |dw:1438191114060:dw|

  3. phi
    • one year ago
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    is 25 a power of 5 ?

  4. anonymous
    • one year ago
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    yes 5^2

  5. phi
    • one year ago
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    do you know that 1/a can be written a^(-1) ?

  6. phi
    • one year ago
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    so if we let 5^2 be "a" for the moment 1/(5^2) = (5^2)^-1 \[ \frac{1}{5^2}= \left(5^2\right)^{-1} \] now use the rule \[ \left(a ^b\right)^c = a^{bc} \]

  7. anonymous
    • one year ago
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    Ok!

  8. anonymous
    • one year ago
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    -5=x

  9. phi
    • one year ago
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    can you show the steps?

  10. anonymous
    • one year ago
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    (5^2)^-1=5^x+4 -1=x+4

  11. anonymous
    • one year ago
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    x=-5

  12. anonymous
    • one year ago
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    oh! I meant -6

  13. phi
    • one year ago
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    the left side is not correct. the rule up above says a "power to a power" ... multiply the powers you get 5^(-2) (and you really should know this: 5^(-2) is the same as 1/5^2 )

  14. phi
    • one year ago
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    -2 = x + 4 and yes you get x= -6

  15. anonymous
    • one year ago
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    Thanks :)

  16. anonymous
    • one year ago
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    And I do know that, I just had a brain fart

  17. phi
    • one year ago
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    yw

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