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K.Binks

  • one year ago

What is the foci of a graphed ellipse?

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  1. K.Binks
    • one year ago
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  2. anonymous
    • one year ago
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    Form this ellipse into the general equation. \[\frac{ x^2 }{ a^2 } + \frac{ y^2 }{ b^2 } = 1\]

  3. anonymous
    • one year ago
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    The ellipse isn't at origin so you need to adjust a little, and use the foci formula \[c^2=a^2-b^2\] c = foci

  4. K.Binks
    • one year ago
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    Ok, so..is the general equation x^2/-1 + y^2/16= 1?and then use those a and b in the new formula?

  5. anonymous
    • one year ago
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    The general equation for this ellipse looks like this \[\frac{ (x-2)^2 }{ 3^2 } +\frac{ (y-2)^2 }{ 2^2 } = 1\]

  6. anonymous
    • one year ago
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    \[c^2=3^2-2^2\]

  7. K.Binks
    • one year ago
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    5? That isn't one of my options.. I'm sorry I'm not understanding this. My options are A) (2 - sqrt5 , 1) and (2 + sqrt5 , 1) B) (2 - sqrt5 , 2) and (2 + sqrt5, 2) C) (2, 1) and (-2, 1) D) (-3, 1) and (3, 1)

  8. anonymous
    • one year ago
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    Its square root 5

  9. anonymous
    • one year ago
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    you need to get your vertex first

  10. anonymous
    • one year ago
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    Your best bet is B

  11. K.Binks
    • one year ago
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    I didn't mean to be given the answer, but thank you

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