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anonymous

  • one year ago

Find the derivative of f(x) = 8/x at x = -1.

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  1. anonymous
    • one year ago
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    @dan815

  2. anonymous
    • one year ago
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    do you know the power rule?

  3. anonymous
    • one year ago
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    no sorry

  4. anonymous
    • one year ago
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    @Peaches15

  5. anonymous
    • one year ago
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    here is if this helps f(x) = 8x^(-1) is the same thing as f(x) = 8/x

  6. anonymous
    • one year ago
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    oh cool

  7. anonymous
    • one year ago
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    now I know the power rule

  8. anonymous
    • one year ago
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    so just bring the -1 down and subtract 1 from the exponent of -1

  9. anonymous
    • one year ago
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    you make no sense lol

  10. anonymous
    • one year ago
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    can you pls show me?

  11. anonymous
    • one year ago
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    f(x) = x^6 • 7e^(7x) + e^(7x) • 6x^5 = e^(7x) (7x^6 + 6x^5) hope this help

  12. anonymous
    • one year ago
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    yeah afcourse y = 8x^(-1) y'= (-1)8x^(-1-1) y' = -8x^(-2)

  13. anonymous
    • one year ago
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    ok what does that do? how does that bring us closer to solving the problem. Pls just list the steps and how to do them for this problem and once I get it once I won't need help again. I will be your 2nd fan and give you medal

  14. anonymous
    • one year ago
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    when you have negative exponents you can bring them to the denominator and then they become positive so youll get y' = -8/x^2

  15. anonymous
    • one year ago
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    ok but how do i find the gosh darn derivative?

  16. anonymous
    • one year ago
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    here plug in your problem into this calculator it shows steps and names the rules that you need to use itll explain it better than i could http://www.derivative-calculator.net/

  17. anonymous
    • one year ago
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    y' = -8/x^2 is the derivative

  18. anonymous
    • one year ago
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    oho thanks

  19. anonymous
    • one year ago
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    see but these are my answers: 4 0 8 -8

  20. anonymous
    • one year ago
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    @phi

  21. anonymous
    • one year ago
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    yeah know you need to plug in the -1 remember from your x = -1 in the question

  22. anonymous
    • one year ago
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    now*

  23. anonymous
    • one year ago
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    ok thanks got it now

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