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okay so basically you have to set on of the equations equal to y and then plug that value you get for y into the other equation
So solve one of them them put the answer in the other equation?
How would you solve the equation?
eq.1 2x+y=1 eq.2 4x+2y=-1 from eq.1 we solve for y so y=1-2x now sub y=1-2x in eq.2 so, 4x+2(1-2x)=-1
okay lets pic the second equation 4x + 2y = -1 subtract the 4x 2y = -1 - 4x divide by 2 y = (-1 - 4x)/2
if you use the first equation the x's cancel out so i didn't use it
so now plug in y = (-1 - 4x)/2 as the y for your fist equation 2x+y = 1
so it would be 2x + (-1-4x)/2=1 ?
and know just solve for x
however im starting to think its d
exactly the x cancels out which is true so there is an option for that...it will still cancel out ussing your way @Jdosio
Thank you for the help it makes more sense how to solve it now.
oh really... thats strange im getting -3/2 is it canceling out for you ?
Yeah it is
So wouldnt it be d if it was canceling out?
anyway depending on how you decide to go about it you get different values for x which leads me to believe that it is d
i would like to think its C"
because the x value cancels leaving -1/2=1 ...
But if the values get canceled out then wouldnt that mean there was just more then one solution
it was my understanding that if you could manage to get any x value then you could cancel out c
i place my bets on d :p
But the equation wasnt set up like that
but let me know if it was D...