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MikeZack123
 one year ago
The length of a rectangle is three times its width.
If the area of the rectangle is 192 yd^2, find its perimeter.
MikeZack123
 one year ago
The length of a rectangle is three times its width. If the area of the rectangle is 192 yd^2, find its perimeter.

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MikeZack123
 one year ago
Best ResponseYou've already chosen the best response.0@dan815 @Michele_Laino @Australopithecus

MikeZack123
 one year ago
Best ResponseYou've already chosen the best response.0@phi @thomaster @undeadknight26

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438200035716:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0p = 2w + 2L L = 3x w = x

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0well look at the problem this way dw:1438199742717:dw so using the area information and the area in terms of width, you can say \[192 = 3w^2\] you need to solve for w as the 1st step when you find the width, then you can find the length, and perimeter hope it helps

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so know jsut plug in thouse values an tell me what p equals in terms of x
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