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anonymous
 one year ago
Am I right?
anonymous
 one year ago
Am I right?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Find the vertex of f(x) = 5x2 + 2x + 1. (2±√(2^24*5*1))/(2*5) (2±√(16))/10 = (2±4)/10 = 2/10 and 6/10

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0no you are incorrect.... it would seem that you have found the x intercepts or the zeros for the quadratic

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh, I mixed up the problem, that is what I was trying to find, LOL. Sorry, working all day on Algebra.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I was trying to find the zeroes. Is it right?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0if this is algebra the 1st step is to find the line of symmetry for the parabola, as the vertex is on the line of symmetry so for a parabola \[y=ax^2 + bx + c\] the line of symmetry is \[x = \frac{b}{2 \times a}\] you have b = 2 and a = 5 when you get the value for x, substitute the x value into the equation to find the minimum value these to values will get the vertex... as a point

phi
 one year ago
Best ResponseYou've already chosen the best response.12/10 and 6/10 you probably should simplify these to 1/5 and 3/5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, I did. So it's right?

phi
 one year ago
Best ResponseYou've already chosen the best response.1oh, one subtlety! \[ \frac{2 \pm \sqrt{16}} {10 } \]

phi
 one year ago
Best ResponseYou've already chosen the best response.1the square root of 16 is sqrt(16) * sqrt(1) or 4 i (we use i for the square root of 1)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So, I put i after the top negative number?

phi
 one year ago
Best ResponseYou've already chosen the best response.1one root is \[ \frac{1}{5} + \frac{2}{5} i \] the other is \[ \frac{1}{5}  \frac{2}{5} i \]

phi
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{2 \pm \sqrt{16}} {10 } \\ \frac{2 \pm 4i }{10 }\\ \frac{2}{10} \pm \frac{4}{10} i \]

phi
 one year ago
Best ResponseYou've already chosen the best response.1and finally \[  \frac{1}{5} \pm \frac{2}{5} i \]

phi
 one year ago
Best ResponseYou've already chosen the best response.1you cannot combine the term with "i" with the "real" term the term with "i" is called the imaginary part and the other part is called the "real part"

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But, isn't the square root of 16, 4?

phi
 one year ago
Best ResponseYou've already chosen the best response.14*4 = 16 (which is obviously not 16) people were very confused about this a few hundred years ago. they finally decided the only way to get 16 was to use \( \sqrt{1} \) and then \[ \sqrt{1} \cdot 4 \cdot \sqrt{1} 4 = \sqrt{1} \cdot \sqrt{1} 16 = 1\cdot 16=16\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, sorry, not very good at math, I'm a history and English guy.

phi
 one year ago
Best ResponseYou've already chosen the best response.1just remember \( \sqrt{16} = 4i \)
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