anonymous
  • anonymous
Just checking to see if this is correct. http://i.imgur.com/VRkkh9V.png
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@radar @thomaster @OregonDuck @phi @dan815 @heretohelpalways @ccieux
anonymous
  • anonymous
@mathway
anonymous
  • anonymous
Do you mind telling me what you got for the bottom and top parts of the figure?

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anonymous
  • anonymous
I just added everything together.
anonymous
  • anonymous
Yes, I know that. Then what did you get for each separate thing?
anonymous
  • anonymous
Er. Nothing. I just added it all >_<
anonymous
  • anonymous
Well you solved the area of a section and then wrote it down and then added it all up together right?
anonymous
  • anonymous
I did 4+4, then the sum of that +2 then the sum of that + 8 (which is the other 4+4) and the sum of that with 5.75
anonymous
  • anonymous
Can you find the area of this? |dw:1438203186061:dw|
anonymous
  • anonymous
4
anonymous
  • anonymous
Wrong
anonymous
  • anonymous
Not the best at this subject. Lol. :/
anonymous
  • anonymous
Area of a triangle is \[\large \sf A~=~ \frac{1}{2} \times Height \times Base\]|dw:1438203298442:dw|
anonymous
  • anonymous
How would you times 1/2 though?
anonymous
  • anonymous
\[\large \sf x \times \frac{1}{2} ~=~ \frac{1x}{2}\]
anonymous
  • anonymous
What? >_<
anonymous
  • anonymous
\[\large \sf 4 \times \frac{1}{2}~=~\frac{1 \times 4}{2}\]
anonymous
  • anonymous
Oh. So it would be 4/2, but thats a improper fraction.
anonymous
  • anonymous
\[\large \sf \frac{4}{2}~=~2\]
anonymous
  • anonymous
So the answer would be 2?
anonymous
  • anonymous
The area of the triangle with sides of 2 and 2 is 2, yes.
anonymous
  • anonymous
So confusing. >_<
anonymous
  • anonymous
|dw:1438203674426:dw|
anonymous
  • anonymous
Can you solve for the top section? |dw:1438203756317:dw|
anonymous
  • anonymous
I got 12, But I have a feeling that is wrong. do I have to do the fraction thing again too? So would it be 1 x 12/2? or something like that.
anonymous
  • anonymous
12 is correct :)
anonymous
  • anonymous
Oh. Lol.
anonymous
  • anonymous
So confusing.
anonymous
  • anonymous
Now onto the bottom part of the figure. |dw:1438203869690:dw|
anonymous
  • anonymous
For now, let's flip it around. |dw:1438203894596:dw|
anonymous
  • anonymous
Now |dw:1438203930484:dw| \[\large \sf A~=~\frac{1}{2} \times height \times base\]
anonymous
  • anonymous
So I got it set up but I don't know how to get the answer. I have 1 x 13.75/2
anonymous
  • anonymous
Well that's not right
anonymous
  • anonymous
Lol, I know. :/
anonymous
  • anonymous
Would I multiply instead?
anonymous
  • anonymous
\[\large \sf \frac{1}{2} \times 8 \times 5.75 \rightarrow \frac{8}{2} \times 5.75\]
anonymous
  • anonymous
Ohhhh
anonymous
  • anonymous
23?
anonymous
  • anonymous
Correct :)
anonymous
  • anonymous
:D
anonymous
  • anonymous
Now add the top part and bottom part together to get the total area :)
anonymous
  • anonymous
45?
anonymous
  • anonymous
12+23=?
anonymous
  • anonymous
>_< Missread lol. 35.
anonymous
  • anonymous
Correct. So the final answer is 35 :)
anonymous
  • anonymous
Lol, damn this stuff is a lot of work. >_<
anonymous
  • anonymous
So the answer to my question is 35?
anonymous
  • anonymous
Yes
anonymous
  • anonymous
Thank you for the help. Lol this helps me a WHOLE lot.
anonymous
  • anonymous
\[\huge \color{aqua}N\color{fuchsia}o \space \color{lime}P \color{orange}r \color{blue}o \color{maroon}b \color{red}l \color{olive}e \color{purple}m \ddot\smile \]

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