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mathmath333
 one year ago
Logarithm question
mathmath333
 one year ago
Logarithm question

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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0\(\large \color{black}{\begin{align}& \text{solve}\hspace{.33em}\\~\\& \log_{2}(92^{x})=10^{\log_{10}(3x)}\hspace{.33em}\\~\\ \end{align}}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hi I dot know this yet sorry

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0mistyped ur name was calling frekels

freckles
 one year ago
Best ResponseYou've already chosen the best response.2\[\log_2(92^x)=10^{\log(3x)} \\ \log_2(92^x)=3x \\ 2^{3x}=92^x \\ 2^{3x}+2^x=9 \\ 2^3 2^{x}+2^x=9 \\ 8 \cdot 2^{x}+2^x=9 \\ \text{ multiply both sides by } 2^x \\ 8 +2^{2x}=9 \cdot 2^{x}\]

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0i didn't understand the second step \(\log_2(92^x)=3x\)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1what happened to 10^log ?? :o

freckles
 one year ago
Best ResponseYou've already chosen the best response.2sorry log_10(x) and 10^x are inverses

freckles
 one year ago
Best ResponseYou've already chosen the best response.2\[10^{\log_{10}(3x)}=3x\] when 3x>0

freckles
 one year ago
Best ResponseYou've already chosen the best response.2and I'm so sorry but I have to go someone is waiting on me

freckles
 one year ago
Best ResponseYou've already chosen the best response.2hey @mathmath333 were you able to finish

freckles
 one year ago
Best ResponseYou've already chosen the best response.2you have a quadratic in terms of 2^x
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