anonymous
  • anonymous
Find all solutions in the interval [0, 2pi). tan x + sec x = 1
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
MY WORK: (sin x/ cos x) + (1/ cos x) = 1 (sin x + 1)/ cos x = 1 Then, I'm stuck. :(
Vocaloid
  • Vocaloid
subtract sec(x) from both sides first tan(x) = 1 - sec(x) then square both sides tan^2(x) = (1-secx)^2 = 1 - 2secx + sec^x then use the trigonometric identity tan^(x) = sec^2(x)-1 to change the left side sec^2(x) - 1 = 1 - 2secx + sec^x can you finish from here?
Vocaloid
  • Vocaloid
ah, a bit of a typo last expression should be sec^2(x) - 1 = 1 - 2secx + sec^2(x)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
So what I was doing is wrong?
Vocaloid
  • Vocaloid
well, not "wrong" but it would be difficult to get an answer by converting tan(x) and sec(x) into sin(x) and cos(x)
Vocaloid
  • Vocaloid
there might be a way to do it your way, but I can't think of an easy way to go from there
anonymous
  • anonymous
Wait, so will it be equal to 0?
Vocaloid
  • Vocaloid
sec^2(x) - 1 = 1 - 2secx + sec^2(x) cancel out sec^2(x) -1 = 1 - 2sec(x) 2sec(x) = 2 sec(x) = 1 then solve for x
anonymous
  • anonymous
Then it is 0. :D
Vocaloid
  • Vocaloid
yea

Looking for something else?

Not the answer you are looking for? Search for more explanations.