@GIL-ojei

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

@GIL.ojei
example, right?
yes

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

\(x \in R^n\), they define \(\vec x =(x_1, x_2)\) and by definition above \(\vec x \in R^n\) must have n-tuples, that is \(\vec x =(x_1,x_2,......,x_n)\) so that if it stops at \(x_2\), then the tuples after it will repeat \(x_2\) in n-1 times. Why n-1? because you have \(x_1 \) there.
Hello
Like in \(\mathbb R^3\), \(vec x =(x_1,x_2,x_3)\) , in topology, if they say \(\vec x=(x_1,x_2)\) \(\in \mathbb R^3\), that is \(vec x=(x_1,x_2,x_2)\), hence \(x_2\) repeats n-1 =3-1=2 times. Got that part??
sir, why did x2 repeat twice?
They define it that way!! like your parents "define" you are GIL.
so that everybody will call you GIL. That is it.
is it from the definition x(x1,x2) den because it is not up R^3
which ought to be (x1,x2,x3)?
Actually, this book is not good. If it is written in other language, I have no comments. But it is written in English, but they changed tuple to topple; scalar to sealar. At the first read, I didn't understand what it means. ha!!
sir please have pity on my and help me out or if you have any self teachable book, you can help with , please do. it means i have to understand this before understanding matric and topological space
Anyway, it is just the way they define the operator. it is not important because it doesn't apply to any other problem.
Again, it is not matric!! it is metric.
ok sir
One more thing!! I didn't take topology yet!!. My friends warned me not to take that course. It is so confused and apply to nowhere.
hahahahahahaah. but it is a call course for me . i have to learn it . ok can you take me metric space?
To the topic I never know before, I can make a SHORT research to know what it is. Don't forget, SHORT, not long.
ok but can you open to page 14 of the book, under remark ,,,, i dont get a thing there

Not the answer you are looking for?

Search for more explanations.

Ask your own question