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\(x \in R^n\), they define \(\vec x =(x_1, x_2)\) and by definition above \(\vec x \in R^n\) must have n-tuples, that is \(\vec x =(x_1,x_2,......,x_n)\) so that if it stops at \(x_2\), then the tuples after it will repeat \(x_2\) in n-1 times. Why n-1? because you have \(x_1 \) there.
Like in \(\mathbb R^3\), \(vec x =(x_1,x_2,x_3)\) , in topology, if they say \(\vec x=(x_1,x_2)\) \(\in \mathbb R^3\), that is \(vec x=(x_1,x_2,x_2)\), hence \(x_2\) repeats n-1 =3-1=2 times. Got that part??
sir, why did x2 repeat twice?
They define it that way!! like your parents "define" you are GIL.
so that everybody will call you GIL. That is it.
is it from the definition x(x1,x2) den because it is not up R^3
which ought to be (x1,x2,x3)?
Actually, this book is not good. If it is written in other language, I have no comments. But it is written in English, but they changed tuple to topple; scalar to sealar. At the first read, I didn't understand what it means. ha!!
sir please have pity on my and help me out or if you have any self teachable book, you can help with , please do. it means i have to understand this before understanding matric and topological space
Anyway, it is just the way they define the operator. it is not important because it doesn't apply to any other problem.
Again, it is not matric!! it is metric.
One more thing!! I didn't take topology yet!!. My friends warned me not to take that course. It is so confused and apply to nowhere.
hahahahahahaah. but it is a call course for me . i have to learn it . ok can you take me metric space?
To the topic I never know before, I can make a SHORT research to know what it is. Don't forget, SHORT, not long.
ok but can you open to page 14 of the book, under remark ,,,, i dont get a thing there