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Loser66
 one year ago
@GILojei
Loser66
 one year ago
@GILojei

This Question is Closed

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0\(x \in R^n\), they define \(\vec x =(x_1, x_2)\) and by definition above \(\vec x \in R^n\) must have ntuples, that is \(\vec x =(x_1,x_2,......,x_n)\) so that if it stops at \(x_2\), then the tuples after it will repeat \(x_2\) in n1 times. Why n1? because you have \(x_1 \) there.

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0Like in \(\mathbb R^3\), \(vec x =(x_1,x_2,x_3)\) , in topology, if they say \(\vec x=(x_1,x_2)\) \(\in \mathbb R^3\), that is \(vec x=(x_1,x_2,x_2)\), hence \(x_2\) repeats n1 =31=2 times. Got that part??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sir, why did x2 repeat twice?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0They define it that way!! like your parents "define" you are GIL.

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0so that everybody will call you GIL. That is it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is it from the definition x(x1,x2) den because it is not up R^3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0which ought to be (x1,x2,x3)?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0Actually, this book is not good. If it is written in other language, I have no comments. But it is written in English, but they changed tuple to topple; scalar to sealar. At the first read, I didn't understand what it means. ha!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sir please have pity on my and help me out or if you have any self teachable book, you can help with , please do. it means i have to understand this before understanding matric and topological space

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0Anyway, it is just the way they define the operator. it is not important because it doesn't apply to any other problem.

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0Again, it is not matric!! it is metric.

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0One more thing!! I didn't take topology yet!!. My friends warned me not to take that course. It is so confused and apply to nowhere.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hahahahahahaah. but it is a call course for me . i have to learn it . ok can you take me metric space?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.0To the topic I never know before, I can make a SHORT research to know what it is. Don't forget, SHORT, not long.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok but can you open to page 14 of the book, under remark ,,,, i dont get a thing there
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