At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

I think I got the equation but not the second part. y=-x^2+36

Would i be right?

the vertex form is- a(x -b)^2 + c
so here we have
y = -a(x - 0)^2 + 36

when y = 0 x = 6
0 = -a(6)^2 + 36 so a = 1
equation is y = -x^2+ 36

its negative before the x^2 because the parabola opens downwards

this is the second part which i don't understand that goes with this equation :(

Ok so which points should I choose? Actually, I'll let you decide.

x = -5 y = -(-5)^2 + 36
x = 4 y = -(4)^2 + 36

so y=41
and y=32
??

so thats 2 values for your linear function

now what do I do?

What would the table look like?

i've done things wrong way round...

Is that a 6?

scrap all that and build the table first - that's what they asked for anyway

What do you mean?

No matter, we can always start over:)

so thats 2 values on our table

-x^2 + 36 = x + 10
x^2 + x - 26 = 0

What what would the table look like?

- yes - thats what we are calculating now

you can solve this by using quadratic formula

Oh sorry!

there will be 2 values for x
you can find the correspondimg values of y by subbing in y = x + 10

Ok! I see :)

|dw:1438212449020:dw|

Alright:)

so then we would need 2 more points correct?

just to check, these are 2 points of intersection?

yes solve the quadratic for x
theh y = x +10 for the 2 values

* 2 y values

yes

ok! But where did the y=x+10 come from?

the first x value will be between -6 and -5 and second will be between 4 and 5

x = (-1 +/- sqrt(1^1 - 4*1*-26)) / 2

ok, so it could be like -4 for the first and idk for the second

alright :)

that comes to x = 4.62 and - 5.62

gtg right now

u still there?