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  • one year ago

1.The following unbalanced equation describes the reaction that can occur when lead (II) sulfide reacts with oxygen gas to produce lead (II) oxide and sulfur dioxide gas: PbS + O2  PbO + SO2 Balance the equation and describe in words the electron transfer(s) that takes place?? Help

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  1. anonymous
    • one year ago
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    2PbS + 3O2  2PbO + 2SO2 It's a reduction, as the Oxygen pass from 0 (in O2) in to -2 (in PbO or S02), so it get electrons.

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