anonymous
  • anonymous
PLEASE HELP!!!
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
square both sides, what do you get?

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anonymous
  • anonymous
I got x = 10, but I'm not sure if that is an extraneous solution or not
anonymous
  • anonymous
show your work, please
anonymous
  • anonymous
|dw:1438221152504:dw|
anonymous
  • anonymous
but when we plug x=10 into the original equation, we have 12=-12, right?
anonymous
  • anonymous
right
anonymous
  • anonymous
so?
anonymous
  • anonymous
I don't know. @dan815
anonymous
  • anonymous
What is the field? Real or Complex?
anonymous
  • anonymous
Real
anonymous
  • anonymous
Actually, with x =10 then \(\sqrt{16}=\pm 4\) and we just use -4 to get the right solution, but I don't know how to argue further if the field is real.
anonymous
  • anonymous
And there is no extraneous solution
Nnesha
  • Nnesha
need help?
Nnesha
  • Nnesha
substitute x by its value if you get equal sides then 10 isn't an extraneous if both sides are not equal then 10 is an extraneous solution

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