1. anonymous

2. anonymous

@jim_thompson5910 @zzr0ck3r

3. anonymous

square both sides, what do you get?

4. anonymous

I got x = 10, but I'm not sure if that is an extraneous solution or not

5. anonymous

6. anonymous

|dw:1438221152504:dw|

7. anonymous

but when we plug x=10 into the original equation, we have 12=-12, right?

8. anonymous

right

9. anonymous

so?

10. anonymous

I don't know. @dan815

11. anonymous

What is the field? Real or Complex?

12. anonymous

Real

13. anonymous

Actually, with x =10 then $$\sqrt{16}=\pm 4$$ and we just use -4 to get the right solution, but I don't know how to argue further if the field is real.

14. anonymous

And there is no extraneous solution

15. Nnesha

need help?

16. Nnesha

substitute x by its value if you get equal sides then 10 isn't an extraneous if both sides are not equal then 10 is an extraneous solution