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anonymous
 one year ago
PLEASE HELP!!!
anonymous
 one year ago
PLEASE HELP!!!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910 @zzr0ck3r

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0square both sides, what do you get?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got x = 10, but I'm not sure if that is an extraneous solution or not

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0show your work, please

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438221152504:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but when we plug x=10 into the original equation, we have 12=12, right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't know. @dan815

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is the field? Real or Complex?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Actually, with x =10 then \(\sqrt{16}=\pm 4\) and we just use 4 to get the right solution, but I don't know how to argue further if the field is real.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And there is no extraneous solution

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0substitute x by its value if you get equal sides then 10 isn't an extraneous if both sides are not equal then 10 is an extraneous solution
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