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anonymous

  • one year ago

You have a 5-question multiple-choice test. Each question has four choices. You don’t know any of the answers. What is the experimental probability that you will guess exactly three out of five questions correctly? Type your answer below using complete sentences.

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  1. misty1212
    • one year ago
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    HI!!

  2. misty1212
    • one year ago
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    binomial should work for this one

  3. misty1212
    • one year ago
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    what is the probability you get any one question right?

  4. misty1212
    • one year ago
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    if you do not know, say so and i can tell you hint, there are 4 possible answers, only one is right

  5. anonymous
    • one year ago
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    I really don't know..

  6. misty1212
    • one year ago
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    one is right, out of four ratio is \(\frac{1}{4}\) i.e. the probability you get any one answer correct is \(\frac{1}{4}\)

  7. misty1212
    • one year ago
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    you also need the probability you get any one answer incorrect you know that?

  8. anonymous
    • one year ago
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    3/4?

  9. triciaal
    • one year ago
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    |dw:1438222812257:dw|

  10. misty1212
    • one year ago
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    yes it is \(\frac{3}{4}\) for wrong answers

  11. misty1212
    • one year ago
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    now you want 3 out of 5, so 3 right, 2 wrong

  12. misty1212
    • one year ago
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    probabiliy of getting any one answer right is \(\frac{1}{4}\) and you want 3 right so \((\frac{1}{4})^3\) also 2 wrong, so \((\frac{3}{4})^2\)

  13. misty1212
    • one year ago
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    then then multiply by the number of ways to choose 3 out of 5 that is called "five choose three" sometimes written as \[\_5C_3\] or more commonly \[\binom{5}{3}\] and computed via \[\binom{5}{3}=\frac{5\times 4}{2}\]

  14. misty1212
    • one year ago
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    final answer is \[10\times \left(\frac{1}{4}\right)^3\times \left(\frac{3}{4}\right)^2\] use a calculator

  15. anonymous
    • one year ago
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    .009765625?

  16. anonymous
    • one year ago
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    hello????/

  17. anonymous
    • one year ago
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    i don''t know i didn't do it hold on

  18. anonymous
    • one year ago
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    http://www.wolframalpha.com/input/?i=10*.25^3*.75^2

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