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anonymous

  • one year ago

Solve the system of equations by substitution. What is the solution for x? 2x + y = 1 4x + 2y = -2 x = 0 x = 2 There is no x value, as there is no solution. x can be any value, as there is an infinite number of solutions.

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  1. anonymous
    • one year ago
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    @jim_thompson5910

  2. LynFran
    • one year ago
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    i did this same question today...

  3. LynFran
    • one year ago
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    choose the last option

  4. LynFran
    • one year ago
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    rewrite eq.1 y=1-2x sub it into eq.2 4x+2(1-2x)=-2 4x+2-4x=-2 2=-2

  5. anonymous
    • one year ago
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    Lemme try Cramer's Rule for this one.

  6. LynFran
    • one year ago
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    as u can see the x cancels so x can be any value, there will be an infinite # of solutions

  7. anonymous
    • one year ago
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    \[\left[\begin{matrix}2 & 1 \\ 4 & 2\end{matrix}\right]\left[\begin{matrix}x \\ y\end{matrix}\right]=\left[\begin{matrix}1 \\ -2\end{matrix}\right]\] \[AB=C\] \[|A| = \left[\begin{matrix}2 & 1 \\ 4 & 2\end{matrix}\right] = (2\times2)-(1\times4)=0\]

  8. anonymous
    • one year ago
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    This systems of equation doesn't work

  9. anonymous
    • one year ago
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    im sorry i still dont understand

  10. anonymous
    • one year ago
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    would the answer be 2=-2 @LynFran

  11. anonymous
    • one year ago
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    There is no x value, as there is no solution.

  12. anonymous
    • one year ago
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    That 2 lines are parallel

  13. LynFran
    • one year ago
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    its not x can carry an infinite # of solution

  14. LynFran
    • one year ago
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    @DecentNabeel check this out lol

  15. anonymous
    • one year ago
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    x cannot be 0 and -2 at the same time in systems of equation.

  16. anonymous
    • one year ago
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    So witch would it be ?

  17. LynFran
    • one year ago
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    check this out its explain in more detail http://openstudy.com/users/decentnabeel#/updates/55b9661ee4b0adef802b9b51

  18. anonymous
    • one year ago
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    If the determinant made from the coefficients equals zero, then there is not a single solution to the system.

  19. LynFran
    • one year ago
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    did u do that by substitution""

  20. anonymous
    • one year ago
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    Nah, I just put em in 2x2 matrix and get determinant

  21. anonymous
    • one year ago
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    If |A| = 0 , the system of equation doesn't work cause you can't divide by zero

  22. anonymous
    • one year ago
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    The original system of equations: 2x + y = 1 4x + 2y = -2 Modify the first equation: y = 1 - 2x Insert that into the second equation, then solve: 4x + 2(1 - 2x) = -2 4x + 2 - 4x = -2 4x - 4x + 2 = -2 2 = -2 The system of equations has no solution.

  23. anonymous
    • one year ago
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    How can 2=-2

  24. anonymous
    • one year ago
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    The point is that 2 does not equal 2. There is no solution to the system of equations.

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