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anonymous
 one year ago
Solve the system of equations by substitution. What is the solution for x?
2x + y = 1
4x + 2y = 2
x = 0
x = 2
There is no x value, as there is no solution.
x can be any value, as there is an infinite number of solutions.
anonymous
 one year ago
Solve the system of equations by substitution. What is the solution for x? 2x + y = 1 4x + 2y = 2 x = 0 x = 2 There is no x value, as there is no solution. x can be any value, as there is an infinite number of solutions.

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LynFran
 one year ago
Best ResponseYou've already chosen the best response.1i did this same question today...

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1choose the last option

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1rewrite eq.1 y=12x sub it into eq.2 4x+2(12x)=2 4x+24x=2 2=2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Lemme try Cramer's Rule for this one.

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1as u can see the x cancels so x can be any value, there will be an infinite # of solutions

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\left[\begin{matrix}2 & 1 \\ 4 & 2\end{matrix}\right]\left[\begin{matrix}x \\ y\end{matrix}\right]=\left[\begin{matrix}1 \\ 2\end{matrix}\right]\] \[AB=C\] \[A = \left[\begin{matrix}2 & 1 \\ 4 & 2\end{matrix}\right] = (2\times2)(1\times4)=0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This systems of equation doesn't work

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im sorry i still dont understand

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would the answer be 2=2 @LynFran

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0There is no x value, as there is no solution.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That 2 lines are parallel

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1its not x can carry an infinite # of solution

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1@DecentNabeel check this out lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x cannot be 0 and 2 at the same time in systems of equation.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So witch would it be ?

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1check this out its explain in more detail http://openstudy.com/users/decentnabeel#/updates/55b9661ee4b0adef802b9b51

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If the determinant made from the coefficients equals zero, then there is not a single solution to the system.

LynFran
 one year ago
Best ResponseYou've already chosen the best response.1did u do that by substitution""

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Nah, I just put em in 2x2 matrix and get determinant

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If A = 0 , the system of equation doesn't work cause you can't divide by zero

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The original system of equations: 2x + y = 1 4x + 2y = 2 Modify the first equation: y = 1  2x Insert that into the second equation, then solve: 4x + 2(1  2x) = 2 4x + 2  4x = 2 4x  4x + 2 = 2 2 = 2 The system of equations has no solution.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The point is that 2 does not equal 2. There is no solution to the system of equations.
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