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\[-\tan^2x+\sec^2x=1\] this?

hmm that's one of the identities only rearranged...

there is a trig identity which is
\[\tan^2x+1 =\sec^2x \]

yes, that is correct (the first response you made)

1 = sec^2x - tan^2x ?

yeah.. now if we rearrange this
\[1=\sec^2x-\tan^2x \]
to
\[1= -\tan^2x+\sec^2x\]

I think there's already an identity which is
\[\tan^2x+1 =\sec^2x \]
then just rearrange the terms.

oh I see where you're going on this...
xD

im confused now :/

is that the final answer?

okay, i see now.

ugh my latex broke

but we got them to equal.. that's the main thing

i understand now, thank you sooo much!!