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anonymous
 one year ago
Determine all points of intersection y=cosX and y=sinX in the first quadrant
anonymous
 one year ago
Determine all points of intersection y=cosX and y=sinX in the first quadrant

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0o my i wish i know..sorry i don't know

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.2sin45=cos45

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.2hope that works

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes I know it's 45(pi/4) but is there any math involved? I found the answer by looking at a graph...

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.2in terms of triangle... well try imagining with random values in which sin and cos value merge....

AakashSudhakar
 one year ago
Best ResponseYou've already chosen the best response.1Well, the more accurate answer would be:\[\frac{ \pi }{ 4 }+2n \pi\]This is because every 2*pi you go out in the positive direction, you'll have another intersection of the cosine and sine graphs in the first quadrant. This is a property generally held true for any intersection relationships between sinusoidal functions.

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.2@AakashSudhakar How will you explain why the pi/4 came? We know its pi/4.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1maybe it's from the 45 degree angle special triangle?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1dw:1438230609757:dw

AakashSudhakar
 one year ago
Best ResponseYou've already chosen the best response.1You can do this either by simply plugging in values into the expression: \[\sin \theta = \cos \theta\]and seeing what works. Or, you can use the unit circle. Create a unit circle, look at the first quadrant, and see which value on the unit circle allows sin(theta) and cos(theta) to traverse the same distance. I prefer the unit circle method, it's much faster and very accurate.
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