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anonymous

  • one year ago

Determine all points of intersection y=cosX and y=sinX in the first quadrant

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  1. anonymous
    • one year ago
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    o my i wish i know..sorry i don't know

  2. arindameducationusc
    • one year ago
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    easy

  3. arindameducationusc
    • one year ago
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    sin45=cos45

  4. arindameducationusc
    • one year ago
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    hope that works

  5. anonymous
    • one year ago
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    Yes I know it's 45(pi/4) but is there any math involved? I found the answer by looking at a graph...

  6. arindameducationusc
    • one year ago
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    in terms of triangle... well try imagining with random values in which sin and cos value merge....

  7. AakashSudhakar
    • one year ago
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    Well, the more accurate answer would be:\[\frac{ \pi }{ 4 }+2n \pi\]This is because every 2*pi you go out in the positive direction, you'll have another intersection of the cosine and sine graphs in the first quadrant. This is a property generally held true for any intersection relationships between sinusoidal functions.

  8. arindameducationusc
    • one year ago
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    @AakashSudhakar How will you explain why the pi/4 came? We know its pi/4.

  9. UsukiDoll
    • one year ago
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    maybe it's from the 45 degree angle special triangle?

  10. UsukiDoll
    • one year ago
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    |dw:1438230609757:dw|

  11. AakashSudhakar
    • one year ago
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    You can do this either by simply plugging in values into the expression: \[\sin \theta = \cos \theta\]and seeing what works. Or, you can use the unit circle. Create a unit circle, look at the first quadrant, and see which value on the unit circle allows sin(theta) and cos(theta) to traverse the same distance. I prefer the unit circle method, it's much faster and very accurate.

  12. AakashSudhakar
    • one year ago
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