## anonymous one year ago A country's population in 1990 was 156 million. In 1996 it was 162 million. Estimate the population in 2016 using the exponential growth formula. Round your answer to the nearest million.

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1. anonymous

@saseal

2. anonymous

@aric200

3. anonymous

$162 = 156(1+x)^{6}$

4. anonymous

So you need to solve for x first

5. anonymous

I just checked this, It seems correct http://openstudy.com/study#/updates/5201dbfbe4b0ebbcb9c6b14d @wolf1728 The population increases156,000,000 to 162,000,000 over 6 years 156,000,000 * (1+r)^6 = 162,000,000 (1+r)^6 = 162,000,000 / 156,000,000 (1+r)^6 = 1.03846153846154 6 * log(1+r) = log(1.03846153846154) log(1+r) = 0.01639041618817 / 6 log(1+r) = 0.0027317360313616 1+r = 1.0063098786004 r = .0063098786004 Testing the value of r 156,000,000 * (1+ .0063098786004)^6 = 1996 population 156,000,000 * 1.03846153846154 = 162,000,000 1996 population r = .0063098786004 Plug r in to find pop in 2016.

6. anonymous

how do I solve for x

7. anonymous

$\frac{ 162 }{ 156 } = (1+x)^6$

8. anonymous

26?

9. anonymous

$1.038461538 = (1+x)^6$ $1.038461538 - 1 =0.38461538$ $\sqrt[6]{0.038461538} = 0.0063$

10. anonymous

could u plz just tell me the answer bc I don't get it

11. anonymous

183.717165048

12. anonymous

13. anonymous

yup

14. anonymous

$2016-1990=26$ $156(1+0.0063098786004)^{26} = 183.717165048$

15. hwyl

stop giving out answers. cheating will not be tolerated

16. wolf1728

To solve for x you need to tale logs of both sides 162/156=(1+x)^6

17. wolf1728

TAKE logs

18. wolf1728

I guess jherbo isn't here anymore