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Welp
 one year ago
Is this correct?
Welp
 one year ago
Is this correct?

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Welp
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438254653856:dw =170^2

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4What are you trying to find? Area?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4What did you do for 170^2

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4\[A_{\square} =a^2~~~~~A_{\triangle} = \frac{ 1 }{ 2 }bh\]

Welp
 one year ago
Best ResponseYou've already chosen the best response.0Oops. I got 306090 mixed up with this. I just tried using soh cah toa and got o=10 a=10 h=10^2, which doesn't make any sense. I'm not sure what to do now

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4I'm going to redraw it, dw:1438255686271:dw does this look right

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4Ok so we know that's a square and a triangle, agree?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4So for the base of the triangle we can simply do \[b = 2212 = 10\] as we know the side of the square is 12, and all the sides of the square are the same.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4dw:1438255835677:dw so we have this now

Welp
 one year ago
Best ResponseYou've already chosen the best response.0It's a rectangle and a triangle

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4Well a square is a special rectangle, but if you could upload an image it would be better, but I think this is right.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4dw:1438255987163:dw

Welp
 one year ago
Best ResponseYou've already chosen the best response.0"Well a square is a special rectangle" Oh http://i.imgur.com/8zzdyhK.png

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think it's a square.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4Yeah me to..looks like a square to me

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Since the height is 12 and the width is 12.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4Yes, it's a square, so now you can get the total area using \[A_{total} = a^2+\frac{ 1 }{ 2 }ab\] Where a = 12 b = 10

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4I'm going to make sure though, lets just use some trig. dw:1438256489005:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4Yeah, so it's not a square...we can use the tan ratio \[\tan \theta = \frac{ opp }{ adj } \implies \tan \theta* adj = opp \implies \tan(45)*10 = opp = 10\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4So this is our new drawing dw:1438256643590:dw that makes much more sense as well

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4because a 45  45  90 triangle would have 10 base and 10 height

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4So we have Area of rectangle + Area of triangle = total area

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4\[A_{total} = lw+\frac{ 1 }{ 2 }bh \]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4The original image was kind of hard to tell, maybe it's because I'm too tired :p But now you should be able to get it, just plug and chug at this stage.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4@Welp Do you understand now? There was just a slight confusion but it's now fixed.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0I'm on openstudy through the old domain... @Astrophysics otherwise I wouldn't get on at all

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.4Yeah, there's a lot of lag for me lol

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0and then click log in

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Much much better thank you.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0thank goodness for the old domain. way better than openstudy.com 's version

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438257780003:dw

Jaynator495
 one year ago
Best ResponseYou've already chosen the best response.1Explosive Diarrhea
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