Is this correct?

- -Welp-

Is this correct?

- chestercat

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- -Welp-

|dw:1438254653856:dw| =170^2

- Astrophysics

What are you trying to find? Area?

- -Welp-

Yes.

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## More answers

- Astrophysics

What did you do for 170^2

- Astrophysics

\[A_{\square} =a^2~~~~~A_{\triangle} = \frac{ 1 }{ 2 }bh\]

- -Welp-

Oops. I got 30-60-90 mixed up with this. I just tried using soh cah toa and got o=10 a=10 h=10^2, which doesn't make any sense. I'm not sure what to do now

- Astrophysics

I'm going to redraw it, |dw:1438255686271:dw| does this look right

- -Welp-

Yes

- Astrophysics

Ok so we know that's a square and a triangle, agree?

- Astrophysics

So for the base of the triangle we can simply do \[b = 22-12 = 10\] as we know the side of the square is 12, and all the sides of the square are the same.

- Astrophysics

|dw:1438255835677:dw| so we have this now

- -Welp-

It's a rectangle and a triangle

- Astrophysics

Well a square is a special rectangle, but if you could upload an image it would be better, but I think this is right.

- Astrophysics

|dw:1438255987163:dw|

- -Welp-

"Well a square is a special rectangle" Oh http://i.imgur.com/8zzdyhK.png

- undeadknight26

I think it's a square.

- Astrophysics

Yeah me to..looks like a square to me

- undeadknight26

Since the height is 12 and the width is 12.

- Astrophysics

Yes, it's a square, so now you can get the total area using \[A_{total} = a^2+\frac{ 1 }{ 2 }ab\]
Where a = 12
b = 10

- Astrophysics

I'm going to make sure though, lets just use some trig. |dw:1438256489005:dw|

- Astrophysics

Yeah, so it's not a square...we can use the tan ratio \[\tan \theta = \frac{ opp }{ adj } \implies \tan \theta* adj = opp \implies \tan(45)*10 = opp = 10\]

- Astrophysics

So this is our new drawing |dw:1438256643590:dw| that makes much more sense as well

- Astrophysics

because a 45 - 45 - 90 triangle would have 10 base and 10 height

- Astrophysics

Boo yeah!

- Astrophysics

So we have Area of rectangle + Area of triangle = total area

- Astrophysics

\[A_{total} = lw+\frac{ 1 }{ 2 }bh \]

- Astrophysics

The original image was kind of hard to tell, maybe it's because I'm too tired :p
But now you should be able to get it, just plug and chug at this stage.

- Astrophysics

@-Welp- Do you understand now? There was just a slight confusion but it's now fixed.

- -Welp-

Yep

- UsukiDoll

I'm on openstudy through the old domain... @Astrophysics otherwise I wouldn't get on at all

- Jhannybean

Link?

- Astrophysics

Yeah, there's a lot of lag for me lol

- UsukiDoll

http://inquus.org/study#/updates/55ba0638e4b0746426de4f76

- UsukiDoll

and then click log in

- Jhannybean

Much much better thank you.

- UsukiDoll

thank goodness for the old domain. way better than openstudy.com 's version

- anonymous

|dw:1438257780003:dw|

- Jaynator495

Explosive Diarrhea

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