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Welp
 one year ago
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Welp
 one year ago
Is this correct? *

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Welp
 one year ago
Best ResponseYou've already chosen the best response.0Area of each hexagonal shape= 24^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 3\sqrt{3} }{ 2 } a^2\]

Welp
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438258025935:dw Sorry

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the area for a hexafonal shape is \[\left(\begin{matrix}3\sqrt{3} \\ 2\end{matrix}\right) a ^{2}\]

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0The area of a hexagon is : \(\dfrac{1}{2}aP\) a = apothem = height of each triangle P = perimeter around the polygon

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0But that formula applies to all polygons.

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438258522083:dw

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0If you choose the center point as the origin, you will find that all the interior sides of the hexagon are congruent, meaning all the interior angles are 60\(^\circ\)

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438258924761:dw

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0Using the special right triangle rule of 306090 triangles, we can find h. \[\tan(60^\circ) = \frac{h}{2} \longrightarrow h=2\tan(60^\circ)\]

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0Now that we have found h, we can find the area of the hexagon. \[\sf \text{ # of sides} \cdot A_{\triangle} = \text{area of hexagon} \]

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0Do you understand? Hope this helps.

Jaynator495
 one year ago
Best ResponseYou've already chosen the best response.0Explosive Diarrhea
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