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-Welp-

  • one year ago

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  1. -Welp-
    • one year ago
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    Area of each hexagonal shape= 24^2

  2. anonymous
    • one year ago
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    \[\frac{ 3\sqrt{3} }{ 2 } a^2\]

  3. anonymous
    • one year ago
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    plug it in and try

  4. -Welp-
    • one year ago
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    |dw:1438258025935:dw| Sorry

  5. anonymous
    • one year ago
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    the area for a hexafonal shape is \[\left(\begin{matrix}3\sqrt{3} \\ 2\end{matrix}\right) a ^{2}\]

  6. anonymous
    • one year ago
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    where a is the side

  7. anonymous
    • one year ago
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    hexagonal

  8. anonymous
    • one year ago
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    24^2 = Not correct

  9. Jhannybean
    • one year ago
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    The area of a hexagon is : \(\dfrac{1}{2}aP\) a = apothem = height of each triangle P = perimeter around the polygon

  10. Jhannybean
    • one year ago
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    But that formula applies to all polygons.

  11. Jhannybean
    • one year ago
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    |dw:1438258522083:dw|

  12. Jhannybean
    • one year ago
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    If you choose the center point as the origin, you will find that all the interior sides of the hexagon are congruent, meaning all the interior angles are 60\(^\circ\)

  13. Jhannybean
    • one year ago
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    |dw:1438258924761:dw|

  14. Jhannybean
    • one year ago
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    Using the special right triangle rule of 30-60-90 triangles, we can find h. \[\tan(60^\circ) = \frac{h}{2} \longrightarrow h=2\tan(60^\circ)\]

  15. Jhannybean
    • one year ago
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    Now that we have found h, we can find the area of the hexagon. \[\sf \text{ # of sides} \cdot A_{\triangle} = \text{area of hexagon} \]

  16. Jhannybean
    • one year ago
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    Do you understand? Hope this helps.

  17. Jaynator495
    • one year ago
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    Explosive Diarrhea

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