anonymous
  • anonymous
Solve: negative 1 over 2 x + 3 = –x + 7 1 over 2 8 –8 2
Algebra
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
are we solving for x?
anonymous
  • anonymous
@mz.inno143
Michele_Laino
  • Michele_Laino
hint: if I multiply both sides of your equation by 2, I get this: \[\Large 2\left( { - \frac{1}{2}x + 3} \right) = 2\left( { - x + 7} \right)\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
answer is 8/3
anonymous
  • anonymous
http://www.cymath.com/answer.php?q=1%20over%202%20x%20%2B%203%20%3D%20%E2%80%93x%20%2B%207
anonymous
  • anonymous
the link shows you the steps to your problem and its also like an online problem solver, i tend to use it a lot and find it very helpful :)
Michele_Laino
  • Michele_Laino
the equation is: negative 1 over 2... @LaurenRoberts
anonymous
  • anonymous
well then @mz.inno143 could just use the link i gave cause it takes you to an online math problem solver and gives you steps :)
anonymous
  • anonymous
thank you guys very great help

Looking for something else?

Not the answer you are looking for? Search for more explanations.