Help please??
Solve 2x2 + 3x + 6 = 0. Round solutions to the nearest hundredth. (4 points)
x ≈ -2.64 and x ≈ 1.14
x ≈ -1.14 and x ≈ 2.64
No real solutions
x ≈ -1.11 and x ≈ -4.89

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- sebaxtiangb

the 2x2 is suppose to be 2x^2? or is it a multiplication?

- anonymous

yes it is supposed to be 2x^2

- sebaxtiangb

first solve the exponent first

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## More answers

- sebaxtiangb

that will be 4x

- sebaxtiangb

then add the 4x and the 3x

- anonymous

7x

- sebaxtiangb

yes

- LynFran

that will not be 4x??

- sebaxtiangb

then the equation is 7x + 3 = 0

- sebaxtiangb

no bc u multiply \[2^2\]

- sebaxtiangb

which is 4

- sebaxtiangb

then add the variables which is 3x and 4x which is 7x and the equation is then 7x + 3 = 0

- sebaxtiangb

then u can solve

- anonymous

still confused and idk why

- sebaxtiangb

what happen?

- anonymous

well i added the variables and got the 7x+3=0

- anonymous

but not sure what comes after

- sebaxtiangb

subtract 3 from both sides

- anonymous

7x=-3

- sebaxtiangb

|dw:1438268045761:dw|

- sebaxtiangb

divide -3 by 7 and then you will your answer

- sebaxtiangb

and then you have to rounded it

- anonymous

okay

- anonymous

its -0.42, but thats not a selective answer choice

- anonymous

- LynFran

the graph of such equation look like this i hope form it u will be able to get ur answer |dw:1438275951759:dw|this means there are imaginary solutions in other words....
and @sebaxtiangb 2x^2 is not equal to 4x
\[(2x)*(2x)=4x ^{2}\]

- anonymous

okau thank you

- anonymous

what would be the answer tho? bc all these answers are just far off from the selective choice ones

- LynFran

if i say imaginary then i mean?

- anonymous

doesnt eexist

- LynFran

they are imaginary solution ...so they are not real..

- anonymous

okay

- anonymous

nvm still lost

- triciaal

the quadratic equation is in the form
ax^2 + bx + c = 0
to solve
|dw:1438269910092:dw|
using your equation identify your a, b and c values and substitute in the equation

- triciaal

to the nearest hundredths means to 2 decimal places. calculate to 3 places then round.
to round if the 3rd digit is 5 or more add 1 to the 2nd place if the 3rd place is less than 5 you drop it.

- anonymous

nvm i basically give up

- triciaal

don't give up I am here to help you

- triciaal

I guarantee you will get it what was posted above would discourage me too

- anonymous

everyone is just confusing and i just dont know what any of this question wants

- triciaal

|dw:1438270220942:dw|

- triciaal

identify your a, b and c what do you get ?

- anonymous

2x^2+3x+6=0

- triciaal

that is your given equation in the correct format now look at the box above and compare the 2 equations tell me what is a what is b and what is c

- anonymous

ok

- triciaal

|dw:1438270578195:dw|

- anonymous

then what

- triciaal

tell me what is a, what is b and what is c

- triciaal

are you here?

- anonymous

i already said

- anonymous

2x^2+3x+6=0

- triciaal

if you want to get this you need to actually read properly and watch your attitude. I am very patient. you gave me the given equation. I said compare the equations and tell me the values of a, b and c

- triciaal

|dw:1438271098708:dw|

- anonymous

i wasnt sayind that with an attitude. i told you i already told you what it was

- triciaal

after you have your values put in the formula I will repost it here

- triciaal

and I am telling you not to tell me you already told me because if you read properly you will see you have not answered what I am asking so we can get the problem done

- triciaal

have you told me what is a, what is b and what is c ? no you have not!

- triciaal

I told you i am here to help you and to make sure you can do the problem in order to do that you need to answer the questions i ask and let me know when something is still not clear

- triciaal

|dw:1438271419320:dw|

- triciaal

here is the formula I reposted
|dw:1438271451098:dw|
now substitute the values in this equation

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