## anonymous one year ago In right ∆PQR, P and Q are acute angles, and cos P is 3/5. What is sin Q? Answers: 4/5 3/5 2/5 3/4

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1. Nnesha

$\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }$|dw:1438273294665:dw|

2. anonymous

sin∠R=PQPR=PQ2PQ=12 So ∠R=? Also i hope you are aware of the fact that in a right angled triangle sinθ=Opposite SideHypotenuse