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anonymous

  • one year ago

Verify the identity. cotx minus pi divided by two. = -tan x

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  1. anonymous
    • one year ago
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    Is the identity pi/2?

  2. David27
    • one year ago
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    @iloveyou;*

  3. anonymous
    • one year ago
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    i suck at math sorry :/

  4. anonymous
    • one year ago
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    @Haseeb96

  5. Haseeb96
    • one year ago
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    sorry i also dont know

  6. Haseeb96
    • one year ago
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    @Nnesha

  7. anonymous
    • one year ago
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    I want to believe the identity is pi/2.

  8. David27
    • one year ago
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    @dan815

  9. David27
    • one year ago
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    @ganeshie8

  10. Nnesha
    • one year ago
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    verify. you need to prove that both sides are equal

  11. Haseeb96
    • one year ago
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    yes

  12. Haseeb96
    • one year ago
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    i have sucked that how to do verify it @Nnesha

  13. Nnesha
    • one year ago
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    remember tan =sin /cos so you can write tan in terms of sin/cos

  14. dan815
    • one year ago
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    hello

  15. dan815
    • one year ago
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    remember complimentary angles for sin and cos

  16. dan815
    • one year ago
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    |dw:1438277241493:dw|

  17. Nnesha
    • one year ago
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    \[\large \rm cot (x - \frac{ \pi }{ 2 }) =\frac{ \cos( \frac{ \pi }{ 2 }- x) }{ \sin(\frac{ \pi }{ 2 } -x)}\] i guess we have to use this formulas http://prntscr.com/7ywjsc :D and btw i meant to say write cot in terms of cos/sin

  18. anonymous
    • one year ago
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    What do we do from here?

  19. dan815
    • one year ago
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    ok well lets fix these errors first

  20. Nnesha
    • one year ago
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    use these two formulas http://prntscr.com/7ywn75

  21. dan815
    • one year ago
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    |dw:1438277549934:dw|

  22. dan815
    • one year ago
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    |dw:1438277660458:dw|

  23. Nnesha
    • one year ago
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    opps the negative sign ~.~

  24. dan815
    • one year ago
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    |dw:1438277743950:dw|

  25. dan815
    • one year ago
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    see why cos(90 deg - x) = sin(x)

  26. dan815
    • one year ago
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    you have a lot of information here, look through this stuff and work out your problem now

  27. Nnesha
    • one year ago
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    and u should remember even/odd formulas \[\cos( - x) = \cos(x)\]\[\sin(-x)=-\sin(x)\]\[\tan(-x)=-\tan(x)\]

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