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anonymous
 one year ago
medal and fan to whoever can answer: y varies inversely with x. Find the constant of the inverse variation equation if x = 3.2 when y = 16. Write your answer as an integer or decimal number.
anonymous
 one year ago
medal and fan to whoever can answer: y varies inversely with x. Find the constant of the inverse variation equation if x = 3.2 when y = 16. Write your answer as an integer or decimal number.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thats the thing... i have no idea how to do this. I tried, but i just dont understand the concept

skullpatrol
 one year ago
Best ResponseYou've already chosen the best response.1Ok, the first thing to look for are the words you don't understand. What does the word "inversely" mean in the phrase "y varies inversely with x"?

skullpatrol
 one year ago
Best ResponseYou've already chosen the best response.1In this context it means y = k/x.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay, but what does k stand for?

skullpatrol
 one year ago
Best ResponseYou've already chosen the best response.1Where the k is the constant of the inverse variation equation.

skullpatrol
 one year ago
Best ResponseYou've already chosen the best response.1Look for what the question is asking for...

skullpatrol
 one year ago
Best ResponseYou've already chosen the best response.1y varies inversely with x. Find the constant of the inverse variation equation if x = 3.2 when y = 16.

skullpatrol
 one year ago
Best ResponseYou've already chosen the best response.1We know the equation has the form y = k/x and we are given: "if x = 3.2 when y =16" Do you have enough info to calculate k?

skullpatrol
 one year ago
Best ResponseYou've already chosen the best response.1dw:1438277129527:dw

skullpatrol
 one year ago
Best ResponseYou've already chosen the best response.1dw:1438277234987:dw

skullpatrol
 one year ago
Best ResponseYou've already chosen the best response.1dw:1438277301383:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you, you really helped :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i completely get it now

skullpatrol
 one year ago
Best ResponseYou've already chosen the best response.1Thanks for trying to learn something new :)
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