## anonymous one year ago The charges on two metallic balls are 5.0 and 7.0 coulombs respectively. They are kept 1.2 meters apart. What is the force of interaction between the two? (k = 9.0 * 10© newton·metersÆ/coulombÆ) A. 2.2 x10^11 newtons B 4.1 x 10^-7 newtons C. 5.0 x 10^11 newtons D. 7.0 x 1-^-7 newtons

1. anonymous

@rvc

2. rvc

$F=\frac{ 1 }{ 4 \pi \epsilon k }\frac{ Q_1O_2 }{ r^2 }$

3. anonymous

i dont know how to plug that in.... @rvc

4. anonymous

i dont get coulombs law or whatever this is

5. rvc

Q_1=5C Q2=7C r=1.2m

6. anonymous

so would it be A? @rvc

7. anonymous

it is A, thank you that really helped! @rvc