## anonymous one year ago ...Easy Medal!! Simplify 4 to the 7th over 5 squared all raised to the 3rd power. 4 to the 10th over 5 to the 5th 4 to the 4th over 5 4 to the 21st over 5 to the 6th 12 to the 7th over 15 squared

1. anonymous

So is it like this? $\large \sf \huge ( \large \frac{4^{7}}{5^{2}} \huge ) ^{3}$

2. anonymous

yes

3. anonymous

4. anonymous

Then you would use the exponent rule: $\large \sf (b^{n})^m~=~b^{n \times m}$

5. anonymous

6. anonymous

$\large \sf (\frac{b^{n}}{a^{l}})^m~=~\frac{b^{n \times m}}{a^{l \times m}}$

7. anonymous

I don't get it

8. anonymous

That's not good

9. anonymous

..