...Easy Medal!! Simplify 4 to the 7th over 5 squared all raised to the 3rd power. 4 to the 10th over 5 to the 5th 4 to the 4th over 5 4 to the 21st over 5 to the 6th 12 to the 7th over 15 squared

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...Easy Medal!! Simplify 4 to the 7th over 5 squared all raised to the 3rd power. 4 to the 10th over 5 to the 5th 4 to the 4th over 5 4 to the 21st over 5 to the 6th 12 to the 7th over 15 squared

Mathematics
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So is it like this? \[\large \sf \huge ( \large \frac{4^{7}}{5^{2}} \huge ) ^{3}\]
yes

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Other answers:

Then you would use the exponent rule: \[\large \sf (b^{n})^m~=~b^{n \times m}\]
which answer would that be
\[\large \sf (\frac{b^{n}}{a^{l}})^m~=~\frac{b^{n \times m}}{a^{l \times m}}\]
I don't get it
That's not good
..

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