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anonymous
 one year ago
How do you approach this one?
equation coming ...
anonymous
 one year ago
How do you approach this one? equation coming ...

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Come up with a reasonably accurate estimate of \[\int\limits_{1}^{\infty} \frac {e^{x}}{ \sqrt{1+ x^{4}}} dx\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you just say that 1/E^x will dominate?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2An estimation w/o knowing the amount of error is useless

dan815
 one year ago
Best ResponseYou've already chosen the best response.0you could expand e^x to a few terms in taylor series

dan815
 one year ago
Best ResponseYou've already chosen the best response.0and state what the error is wrt to how many terms u expand upto

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Im not sure what you mean Dan..sorry.. If 1/E^x is dominant then the function is heading to 0 is there some way of just using the fundamental formula here? If I plot this function it seems to zero out by the time it hits 15, what if I integrate and then just do something like If f'[x] = Power[E, x]/Sqrt[1 + x^4] Then the integration of f'[x] is f[15]  f[1]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and I get 1.903373417798832 * 10^8

dan815
 one year ago
Best ResponseYou've already chosen the best response.0u can use those other approximation methods u are doing there too

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay.. so I don't know if this will be correct but after concluding that the dominant term 1/E^x will approach zero, then examining the plot and seeing that the function approaches zero by about x=15, then taking the definite integral over several intervals of [1,15] [1,30] [1,100] , then I found to within 3 decimal places, the function converges upon 0.127
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