anonymous one year ago Two metal balls have charges of 7.1 * 10ÈÒ coulombs and 6.9 * 10ÈÒ coulombs. They are 5.7 * 10È¹ meters apart. What is the force of interaction between the two balls? (k = 9.0 * 10© newton·metersÆ/coulombÆ) A. 5.7 newtons B. 6.9 newtons C. 7.1 newtons D. 1.4 newtons

1. anonymous

help me with this one please!? @rvc

2. Michele_Laino

hint: the magnitude of the requested force, is given by the Coulomb's law: $\Large F = K\frac{{{Q_1}{Q_2}}}{{{d^2}}}$ where Q1, Q2 are the electric charges, d is the distance between the metal balls

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