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## anonymous one year ago A football quarterback has 2 more chances to throw a touchdown before his team is forced to punt the ball. He misses the receiver on the first throw 30% of the time. When his first throw is incomplete, he misses the receiver on the second throw 10% of the time. What is the probability of not throwing the ball to a receiver on either throw?

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1. anonymous

3/20 would be the right answer I think, but i don't know for sure.

2. anonymous

or 15%

3. kropot72

Let A be the event he misses on the first throw. P(A) = 0.3 Let B be the event he misses on the second throw. Then P(B|A) = 0.1 $\large P(A\cap B)=P(A)\times P(B|A)=0.3\times0.1=0.03$

4. kropot72

If the probability of not throwing the ball to a receiver on either throw is expressed as a percentage it is 0.03 * 100 = 3%.

5. anonymous

are you sure that is right how did you get that? @Pencera

6. anonymous

no im not i said that in my answer

7. anonymous

i apologize

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