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anonymous

  • one year ago

How do you solve this? (Explain please)

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  1. anonymous
    • one year ago
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    \[\sum_{n=1}^{3}\frac{ 1 }{ n ^{3} }\]

  2. anonymous
    • one year ago
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    okay so basically in this problem you have to add the values of \[(1/1^3) + (1/2^3) + (1/3^3)\]

  3. anonymous
    • one year ago
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    you see that n =1 one at the bottom of the sigma

  4. anonymous
    • one year ago
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    that means you start with 1

  5. anonymous
    • one year ago
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    Oh does the three on the top mean you end with 3?

  6. anonymous
    • one year ago
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    yes exactly, if it was say 6 you would keep adding the equations with variables up to 6

  7. anonymous
    • one year ago
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    if at the bottom it said n=3 you would start at three, its a rather hard concept to wrap your head around do you get it?

  8. anonymous
    • one year ago
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    Oh okay. So the answer would be 195/162?

  9. anonymous
    • one year ago
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    fun fact if instead of a \[\sum_{?}^{?} you see a \prod_{?}^{?} \it means multiply \]

  10. anonymous
    • one year ago
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    instead of add

  11. anonymous
    • one year ago
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    dont know havent worked it out give me a sec

  12. anonymous
    • one year ago
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    Alright

  13. anonymous
    • one year ago
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    strange i got 251/216

  14. anonymous
    • one year ago
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    Did u add 1 + 1/6 + 1/27?

  15. LynFran
    • one year ago
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    thats correct @Jdosio

  16. anonymous
    • one year ago
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    no you have to add 1+ 1/8 + 1/27

  17. anonymous
    • one year ago
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    Oh whoops! I messed up on that. Thanks!

  18. anonymous
    • one year ago
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    yep no problem :D

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