## anonymous one year ago The force of repulsion between two like-charged table tennis balls is 8.2 * 10È¥ newtons. If the charge on the two objects is 6.7 * 10È© coulombs each, what is the distance between the two charges? (k = 9.0 * 10© newton·metersÆ/coulombÆ) a: 0.23 b: 0.70 c:6.7 d:8.2

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1. IrishBoy123

Coulomb's Law: $$\large F = k \frac{q_1 \ q_2 }{r^2}$$ $$q_1 = q_2$$