anonymous
  • anonymous
TWO ALGEBRA 2 QUESTIONS! CAN SOMEONE HLEP ME WORK THROUGH THEM?
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
2 Attachments
campbell_st
  • campbell_st
ok... I'd say you need to draw a diagram and plot the point |dw:1438286130188:dw| find x using pythagoras
campbell_st
  • campbell_st
|dw:1438286207877:dw| now you have an angle you can find the trig ratios you need...

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anonymous
  • anonymous
how do I do that?
campbell_st
  • campbell_st
the 2nd question needs pythagoras again find XY then you can find your trig ratios
campbell_st
  • campbell_st
if you are doing trigonometry you should know about Pythagoras' Theorem c^2 = a^2 + b^2
anonymous
  • anonymous
I know about that theorem
campbell_st
  • campbell_st
then you need to find the missing sides in each triangle... then you can find the necessary trig ratios
anonymous
  • anonymous
can you help me?
campbell_st
  • campbell_st
so in the 1st question, what is the measure of the missing side x.?
anonymous
  • anonymous
169
campbell_st
  • campbell_st
close... remember that is x^2 = 169 what is x..?
anonymous
  • anonymous
x=13 or -13?
campbell_st
  • campbell_st
great x = 13 so you know |dw:1438286923320:dw| you are asked to find csc and sec csc... find sin for sec find cos what do you get..?
anonymous
  • anonymous
i don't know how to do that
campbell_st
  • campbell_st
sin =opp/hyp cos=adj/hyp
anonymous
  • anonymous
12/5 5/13
anonymous
  • anonymous
is that is??
anonymous
  • anonymous
it*
campbell_st
  • campbell_st
well in the triangle 13 = hyp 5 = adj and 12 = opp you got cos correct cos = 5/13 sin = 12/13 to find sec just flip the cos fraction to find csc flip the sin fraction
anonymous
  • anonymous
oh, so it is D??
campbell_st
  • campbell_st
nope not D flip the fraction.... turn them upside down if cos = 5/13 what does sec = ? turn the fraction upside down... same for sin = 12/13 csc = ?? turn the sin fraction upside down
anonymous
  • anonymous
13/5 13/12
campbell_st
  • campbell_st
correct
anonymous
  • anonymous
C
campbell_st
  • campbell_st
yes
anonymous
  • anonymous
Can you help me with the other please?

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