A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

Help Would Be Greatly Appreciated.

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The function f(t) = t2 + 12t − 18 represents a parabola. Part A: Rewrite the function in vertex form by completing the square. Show your work. (6 points) Part B: Determine the vertex and indicate whether it is a maximum or a minimum on the graph. How do you know? (2 points) Part C: Determine the axis of symmetry for f(t). (2 points)

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @welshfella @Wxlfz @foreverthebeast @triciaal @ganeshie8 @campbell_st

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @dan815 @jim_thompson5910 @jagr2713 @Nnesha @undeadknight26

  4. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    vertex form a(x-h)^2 + k h = -b/(2a) k = f(h)

  5. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'm lost.

  6. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1438288504884:dw|

  7. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    vertex (h, k)

  8. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    the vertex is the point with maximum or minimum y value when a is positive then y is positive and the vertex is a maximum when a is negative then y is negative and the vertex is at the minimum

  9. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1438289057781:dw|

  10. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Part A: f(t) = t^2 + 12t − 18 f(t) = (t + 12/2)^2 - (12/2)^2 − 18 f(t) = (t + 6)^2 - 36 − 18 f(t) = (t + 36) - 36 − 18 f(t) = t − 18

  11. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @triciaal

  12. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1438289240219:dw|

  13. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Where did you get 12t from?

  14. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    It;s not making sense.

  15. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    what do you mean? look at the original

  16. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    In both the second t disappears.

  17. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ok, so here we go.

  18. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    you have a parabola t^2 + 12t -18 to find the zeros set = 0 and solve

  19. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    f(t) = t^2 + 12t − 18 f(t) = (t + 12/2)^2 - (12/2)^2 − 18 f(t) = (t + 6)^2 - 36 − 18 f(t) = (t^2 + 36) - 36 − 18 f(t) = t^2 − 18

  20. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    What did I do wrong?

  21. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    No writing, just type please.

  22. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    4 th line is wrong and set = 0

  23. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok, what needs to happen in line 4?

  24. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1438289870837:dw|

  25. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Part A: t^2 + 12t − 18 = 0 (t + 12/2)^2 - (12/2)^2 − 18 = 0 (t + 6)^2 - 36 − 18 = 0 (t + 6)^2 = t^2 + 12t + 36

  26. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    @jim_thompson5910 can you continue please I have to leave

  27. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    @Nnesha @dan815 I have to leave

  28. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @dan815 @jim_thompson5910 @undeadknight26 @robtobey @Elsa213 @zzr0ck3r

  29. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    now take (t + 6)^2 - 36 − 18 and simplify to get (t + 6)^2 - 54

  30. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    compare (t + 6)^2 - 54 to the form a(x-h)^2 + k in this case, 't' takes the place of 'x'

  31. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    the vertex of y = a(x-h)^2 + k is (h,k)

  32. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ok, well, t needs to go outside of the parentheses.

  33. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    what do you mean?

  34. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Well, it's no the same form, the only difference is the t (or a) being outside of the parentheses.

  35. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    think of (t + 6)^2 - 54 as 1(t + 6)^2 - 54

  36. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    MISSING t (t + 6)^2 - 54 to the form a(x-h)^2 + k

  37. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ahh, ok.

  38. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    I'm going to replace t with x 1(x + 6)^2 - 54 1(x - (-6))^2 - 54 The expression 1(x - (-6))^2 - 54 is in the form a(x-h)^2 + k a = 1 h = -6 k = -54

  39. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ok

  40. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Is this correct? Part A: t^2 + 12t − 18 = 0 (t + 12/2)^2 - (12/2)^2 − 18 = 0 (t + 6)^2 - 36 − 18 = 0 (t + 6)^2 - 54

  41. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    yeah it looks good

  42. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    what's the vertex of (t + 6)^2 - 54

  43. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Not, sure, Mathway couldn't calculate an answer.

  44. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    -54?

  45. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    Do you see how I wrote (x+6)^2 - 54 into 1(x - (-6))^2 - 54 ?

  46. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yes

  47. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    (-6, -54)

  48. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @jim_thompson5910

  49. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    yes that is the vertex

  50. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ok, was is is and why?

  51. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    huh?

  52. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Determine the vertex and indicate whether it is a maximum or a minimum on the graph. How do you know?

  53. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Vertex: (-6, -54), this is a minimum because because the parabola is pointing down.

  54. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    is that right?

  55. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    yeah it looks like this |dw:1438291343433:dw|

  56. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    |dw:1438291350542:dw|

  57. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Part C: Axis of symmetry is -6.

  58. jim_thompson5910
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 3

    more like x = -6, but yeah

  59. triciaal
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    @jim_thompson5910 thanks

  60. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.