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anonymous
 one year ago
Help Would Be Greatly Appreciated.
anonymous
 one year ago
Help Would Be Greatly Appreciated.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The function f(t) = t2 + 12t − 18 represents a parabola. Part A: Rewrite the function in vertex form by completing the square. Show your work. (6 points) Part B: Determine the vertex and indicate whether it is a maximum or a minimum on the graph. How do you know? (2 points) Part C: Determine the axis of symmetry for f(t). (2 points)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@welshfella @Wxlfz @foreverthebeast @triciaal @ganeshie8 @campbell_st

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@dan815 @jim_thompson5910 @jagr2713 @Nnesha @undeadknight26

triciaal
 one year ago
Best ResponseYou've already chosen the best response.2vertex form a(xh)^2 + k h = b/(2a) k = f(h)

triciaal
 one year ago
Best ResponseYou've already chosen the best response.2dw:1438288504884:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.2the vertex is the point with maximum or minimum y value when a is positive then y is positive and the vertex is a maximum when a is negative then y is negative and the vertex is at the minimum

triciaal
 one year ago
Best ResponseYou've already chosen the best response.2dw:1438289057781:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Part A: f(t) = t^2 + 12t − 18 f(t) = (t + 12/2)^2  (12/2)^2 − 18 f(t) = (t + 6)^2  36 − 18 f(t) = (t + 36)  36 − 18 f(t) = t − 18

triciaal
 one year ago
Best ResponseYou've already chosen the best response.2dw:1438289240219:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Where did you get 12t from?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It;s not making sense.

triciaal
 one year ago
Best ResponseYou've already chosen the best response.2what do you mean? look at the original

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0In both the second t disappears.

triciaal
 one year ago
Best ResponseYou've already chosen the best response.2you have a parabola t^2 + 12t 18 to find the zeros set = 0 and solve

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0f(t) = t^2 + 12t − 18 f(t) = (t + 12/2)^2  (12/2)^2 − 18 f(t) = (t + 6)^2  36 − 18 f(t) = (t^2 + 36)  36 − 18 f(t) = t^2 − 18

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What did I do wrong?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No writing, just type please.

triciaal
 one year ago
Best ResponseYou've already chosen the best response.24 th line is wrong and set = 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok, what needs to happen in line 4?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.2dw:1438289870837:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Part A: t^2 + 12t − 18 = 0 (t + 12/2)^2  (12/2)^2 − 18 = 0 (t + 6)^2  36 − 18 = 0 (t + 6)^2 = t^2 + 12t + 36

triciaal
 one year ago
Best ResponseYou've already chosen the best response.2@jim_thompson5910 can you continue please I have to leave

triciaal
 one year ago
Best ResponseYou've already chosen the best response.2@Nnesha @dan815 I have to leave

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@dan815 @jim_thompson5910 @undeadknight26 @robtobey @Elsa213 @zzr0ck3r

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3now take (t + 6)^2  36 − 18 and simplify to get (t + 6)^2  54

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3compare (t + 6)^2  54 to the form a(xh)^2 + k in this case, 't' takes the place of 'x'

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3the vertex of y = a(xh)^2 + k is (h,k)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, well, t needs to go outside of the parentheses.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3what do you mean?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well, it's no the same form, the only difference is the t (or a) being outside of the parentheses.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3think of (t + 6)^2  54 as 1(t + 6)^2  54

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0MISSING t (t + 6)^2  54 to the form a(xh)^2 + k

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3I'm going to replace t with x 1(x + 6)^2  54 1(x  (6))^2  54 The expression 1(x  (6))^2  54 is in the form a(xh)^2 + k a = 1 h = 6 k = 54

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is this correct? Part A: t^2 + 12t − 18 = 0 (t + 12/2)^2  (12/2)^2 − 18 = 0 (t + 6)^2  36 − 18 = 0 (t + 6)^2  54

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3yeah it looks good

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3what's the vertex of (t + 6)^2  54

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Not, sure, Mathway couldn't calculate an answer.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3Do you see how I wrote (x+6)^2  54 into 1(x  (6))^2  54 ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3yes that is the vertex

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, was is is and why?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Determine the vertex and indicate whether it is a maximum or a minimum on the graph. How do you know?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Vertex: (6, 54), this is a minimum because because the parabola is pointing down.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3yeah it looks like this dw:1438291343433:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3dw:1438291350542:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Part C: Axis of symmetry is 6.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.3more like x = 6, but yeah

triciaal
 one year ago
Best ResponseYou've already chosen the best response.2@jim_thompson5910 thanks
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