anonymous
  • anonymous
A pitcher throws a baseball straight into the air with a velocity of 72 feet/sec. If acceleration due to gravity is −32 ft/sec2, how many seconds after it leaves the pitcher's hand will it take the ball to reach its highest point? Assume the position at time t = 0 is 0 feet.
Mathematics
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SOLVED
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chestercat
  • chestercat
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welshfella
  • welshfella
use an equation for constant acceleration u = initial velocity = 72 , a = -32, t = ? , v = final velocity = 0 v = u + at 0 = 72 - 32t solve for t
anonymous
  • anonymous
2.25?
welshfella
  • welshfella
72 / 32 = 2.25 yes

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anonymous
  • anonymous
thank you!
welshfella
  • welshfella
yw
welshfella
  • welshfella
i'm meeting so many people who dont say thanks today....
anonymous
  • anonymous
Its common courtesy to say thank you :p
anonymous
  • anonymous
especially for an answer
welshfella
  • welshfella
yes

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