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anonymous
 one year ago
A pitcher throws a baseball straight into the air with a velocity of 72 feet/sec. If acceleration due to gravity is −32 ft/sec2, how many seconds after it leaves the pitcher's hand will it take the ball to reach its highest point? Assume the position at time t = 0 is 0 feet.
anonymous
 one year ago
A pitcher throws a baseball straight into the air with a velocity of 72 feet/sec. If acceleration due to gravity is −32 ft/sec2, how many seconds after it leaves the pitcher's hand will it take the ball to reach its highest point? Assume the position at time t = 0 is 0 feet.

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welshfella
 one year ago
Best ResponseYou've already chosen the best response.2use an equation for constant acceleration u = initial velocity = 72 , a = 32, t = ? , v = final velocity = 0 v = u + at 0 = 72  32t solve for t

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2i'm meeting so many people who dont say thanks today....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Its common courtesy to say thank you :p

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0especially for an answer
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