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anonymous

  • one year ago

A pitcher throws a baseball straight into the air with a velocity of 72 feet/sec. If acceleration due to gravity is −32 ft/sec2, how many seconds after it leaves the pitcher's hand will it take the ball to reach its highest point? Assume the position at time t = 0 is 0 feet.

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  1. welshfella
    • one year ago
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    use an equation for constant acceleration u = initial velocity = 72 , a = -32, t = ? , v = final velocity = 0 v = u + at 0 = 72 - 32t solve for t

  2. anonymous
    • one year ago
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    2.25?

  3. welshfella
    • one year ago
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    72 / 32 = 2.25 yes

  4. anonymous
    • one year ago
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    thank you!

  5. welshfella
    • one year ago
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    yw

  6. welshfella
    • one year ago
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    i'm meeting so many people who dont say thanks today....

  7. anonymous
    • one year ago
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    Its common courtesy to say thank you :p

  8. anonymous
    • one year ago
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    especially for an answer

  9. welshfella
    • one year ago
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    yes

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