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The function H(t) = −16t2 + 60t + 95 shows the height H(t), in feet, of a projectile after t seconds. A second object moves in the air along a path represented by g(t) = 20 + 38.7t, where g(t) is the height, in feet, of the object from the ground at time t seconds. Part A: Create a table using integers 1 through 4 for the 2 functions. Between what 2 seconds is the solution to H(t) = g(t) located? How do you know? (6 points) Part B: Explain what the solution from Part A means in the context of the problem. (4 points)
I'm working on the table
i don't think I'm doing it right, can you do the last two on your own while I do them? We check on each others.
well... try to do the table see what you get... and post it, if you need to, just take a screenshot of it or paste here
Time 1 2 3 4 H(t) 411 1239 2579 4431 g(t) 58.7 97.4 136.1 174.8
Not sure what I did wrong. I plugged in all the numbers and solved. @jim_thompson5910
Unless this is right https://nz.answers.yahoo.com/question/index?qid=20150728100650AAh5ZPo
I'm not getting those values
Hmmm... What should I do?
if t = 1, then h(t) = -16t^2 + 60t + 95 h(1) = -16(1)^2 + 60(1) + 95 h(1) = -16(1) + 60(1) + 95 h(1) = -16 + 60 + 95 h(1) = 139
do the same for t = 2 through t = 4
Let's do the second part "Part B: Explain what the solution from Part A means in the context of the problem. (4 points)"
Part B: The solution for Part A has meaning in the context of the problem by showing how many seconds it would take for both objects to be at the same height.
Is that correct?
yes, I'd say so
yeah the point of intersection represents when h(t) = g(t) at the same time value t
your table for part A is off though
look back at how I computed h(1)