-Welp-
  • -Welp-
The triangles are similar. Give the ratio of the perimeters and ratio of the areas of the areas of the first figure to the second. ^How do I solve this?
Geometry
schrodinger
  • schrodinger
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campbell_st
  • campbell_st
well the the ratio of the areas is the square of the ratio of the perimeters
campbell_st
  • campbell_st
so f the perimeters are in the ratio 2:3 the areas will be in the ratio 4:9 so if the area of the 1st figure is 20 then the area of the 2nd is (20/5)*9 = 36 hope it makes sense
-Welp-
  • -Welp-
|dw:1438309389119:dw|

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-Welp-
  • -Welp-
I'm sorry, I don't understand.
-Welp-
  • -Welp-
halp
campbell_st
  • campbell_st
so the ratio of the measurements is 32:28 which simplifies to 8:7 so the ratio of the areas is \[8^2:7^2\] this is because the side length is a 1 dimension measurement and area is a 2 dimension measurement.

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