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-Welp-

  • one year ago

The triangles are similar. Give the ratio of the perimeters and ratio of the areas of the areas of the first figure to the second. ^How do I solve this?

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  1. campbell_st
    • one year ago
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    well the the ratio of the areas is the square of the ratio of the perimeters

  2. campbell_st
    • one year ago
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    so f the perimeters are in the ratio 2:3 the areas will be in the ratio 4:9 so if the area of the 1st figure is 20 then the area of the 2nd is (20/5)*9 = 36 hope it makes sense

  3. -Welp-
    • one year ago
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    |dw:1438309389119:dw|

  4. -Welp-
    • one year ago
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    I'm sorry, I don't understand.

  5. -Welp-
    • one year ago
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    halp

  6. campbell_st
    • one year ago
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    so the ratio of the measurements is 32:28 which simplifies to 8:7 so the ratio of the areas is \[8^2:7^2\] this is because the side length is a 1 dimension measurement and area is a 2 dimension measurement.

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