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anonymous
 one year ago
Find the sine, cosine, and tangent of 360 degrees. @zzr0ck3r @SithsAndGiggles
anonymous
 one year ago
Find the sine, cosine, and tangent of 360 degrees. @zzr0ck3r @SithsAndGiggles

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4you can use *unit circle * where cos is xcoordinate and sin  is ycoordinate and tan = sin over cos

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4without calculator you need to apply 454590 triangle theorem or 306090

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438299380960:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0check your Unit Circle as Nnesha suggested

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok. what do i look for

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4thats why just use unit circle instead 454590 theorem

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4do you have unit circle sheet ? if not then google it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i look for 360 on the unit circle?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0there is none because 360 IS 0 and vice versa right?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.40 doesn't mean *nothing* :=)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4there is an order pair right (x,y) where x=cos y =sin

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4yes so sin 360 = ? and cos 360 = ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sin 360 = 0 cos 360 = 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok thx. what about this one. The point (1, −1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of θ? Make sure to show all work.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i find where the point 1 and 1 are at

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4you have to draw a right triangle

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4wait a sec i have to refresh the page *lag is real*

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4given point is (1,1) so cos =1 (positive ) sin = 1 ( negative ) so at which quadrant cos is positive but sin is negative remember the CAST rule ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4dw:1438300117250:dw now you need to find hyp apply Pythagorean theorem and find 3rd side of right triangle

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4Pythagorean theorem a^2 +b^2 = c^2 where c is hypotenuse longest side of right triangle

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4if you have question , let me know plz :=)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4dw:1438301856130:dw a=1 b=1 c= ? use that formula \[\huge\rm a^2+b^2=c^2\] substitute a for 1 substitute b for 1 solve for c

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4first of all take square of a and b

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4\[\huge\rm 1^2 +(1)^2=c^2\] solve for c

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4yes right so c^2=2 now take square root both sides bec you need c not c^2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4yep right dw:1438302263294:dw so what is sin theta = ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4\[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\] remember this

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so sin theta = 1/root 2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4yes right you can't leave the radical at the denominator so multiply both denoimnator and numerator by sqr root 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0root 2 sin theta = 1?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4correction:\[\frac{ 1 }{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so thats answer to cos?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4nope sin theta = 1 over square root 2 you can't have the radical at the denominator thats why multiply numerator and denominator by square root 2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4\[\frac{ 1 }{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} }\] multiply

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4alright i have to go,too we will continue later

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4:\[\frac{ 1 }{ \sqrt{2} } \times \frac{ \sqrt{2} }{ \sqrt{2} }\] here multiply numerator by numerator and denominator by denominator\[\frac{ 1 \times \sqrt{2} }{ \sqrt{2} \times \sqrt{2}}\] sqrt{2} times sqrt{2} = sqrt{4} which is equal to 2 you will get \[\frac{ \sqrt{2} }{ 2 }\] now at what degrree sin equal to sqrt{2} over 2 ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4same way to find value of cos that's it!

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4if you have any question let me know tomorrow. :=)
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