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anonymous

  • one year ago

PLEASE HELP! Geometry homework!

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  1. anonymous
    • one year ago
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    Link: http://GeometryBits.com/GeoGames/CA/RECache1.html

  2. jdoe0001
    • one year ago
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    ?

  3. anonymous
    • one year ago
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    The link will take you to my homework. You commented this last time I posted. @jdoe0001

  4. jdoe0001
    • one year ago
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    maybe your link is kinda dead, unless someone has an account for the server anyhow... posting specifics helps

  5. anonymous
    • one year ago
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    Triangles ABC and BCD are right triangles. If AB = 6, AC = 10, and CD = 15, a) find BC. b) find BD.

  6. anonymous
    • one year ago
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    you can use the Pythagorean Theorem (a^2+b^2=c^2) C is always the biggest sid and A and B are the other two parts of the triangle (it doesnt matter which is which) c=AC=10 and AB = either a or b (again doesn't matter). so now you have a^2+6^2=10^2

  7. anonymous
    • one year ago
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    now just find for a

  8. anonymous
    • one year ago
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    to do that you have to salve it all for what you can so you get a^2+36=100 now subtract 36 from both sides and you get a^2=64 Now you have to square-root the both sides to get rid of the ^2 and you get a=8

  9. anonymous
    • one year ago
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    a= the missing side which was BC

  10. anonymous
    • one year ago
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    now that you have BC and you fine out BD with the same process a^2+8^2=15^2. you then simplify and get a^2+64=225

  11. anonymous
    • one year ago
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    subtract 64 from both sides and get a^2=161 the you square root it and get a=12.7=BD

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