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maybe your link is kinda dead, unless someone has an account for the server
anyhow... posting specifics helps
Triangles ABC and BCD are right triangles.
If AB = 6, AC = 10,
and CD = 15,
a) find BC.
b) find BD.
you can use the Pythagorean Theorem (a^2+b^2=c^2) C is always the biggest sid and A and B are the other two parts of the triangle (it doesnt matter which is which) c=AC=10 and AB = either a or b (again doesn't matter). so now you have a^2+6^2=10^2
now just find for a
to do that you have to salve it all for what you can so you get a^2+36=100 now subtract 36 from both sides and you get a^2=64 Now you have to square-root the both sides to get rid of the ^2 and you get a=8
a= the missing side which was BC
now that you have BC and you fine out BD with the same process a^2+8^2=15^2.
you then simplify and get a^2+64=225
subtract 64 from both sides and get a^2=161 the you square root it and get a=12.7=BD