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anonymous
 one year ago
PLEASE HELP! Geometry homework!
anonymous
 one year ago
PLEASE HELP! Geometry homework!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The link will take you to my homework. You commented this last time I posted. @jdoe0001

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0maybe your link is kinda dead, unless someone has an account for the server anyhow... posting specifics helps

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Triangles ABC and BCD are right triangles. If AB = 6, AC = 10, and CD = 15, a) find BC. b) find BD.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you can use the Pythagorean Theorem (a^2+b^2=c^2) C is always the biggest sid and A and B are the other two parts of the triangle (it doesnt matter which is which) c=AC=10 and AB = either a or b (again doesn't matter). so now you have a^2+6^2=10^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0to do that you have to salve it all for what you can so you get a^2+36=100 now subtract 36 from both sides and you get a^2=64 Now you have to squareroot the both sides to get rid of the ^2 and you get a=8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0a= the missing side which was BC

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now that you have BC and you fine out BD with the same process a^2+8^2=15^2. you then simplify and get a^2+64=225

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0subtract 64 from both sides and get a^2=161 the you square root it and get a=12.7=BD
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