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anonymous

  • one year ago

If h(x) = g[f(x)], use the table of values for f, g, f ′ and g ′ to find the value of h ′(1)

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  1. anonymous
    • one year ago
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    x f(x) g(x) f ′(x) g ′(x) 1 3 2 2 6 2 1 8 5 7 3 7 2 7 9

  2. anonymous
    • one year ago
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    @LynFran @pooja195

  3. Loser66
    • one year ago
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    First off, h'(x) =??

  4. anonymous
    • one year ago
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    i have no idea

  5. anonymous
    • one year ago
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    would the product rule apply?

  6. anonymous
    • one year ago
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    do i just derive g and f?

  7. Loser66
    • one year ago
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    it's chain rule, not product rule

  8. anonymous
    • one year ago
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    okay so then it would be h'(x) = g'(f(x)) + g(f'(x))?

  9. anonymous
    • one year ago
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    or is it h'(x) = g'(f(x)) * f'(x)

  10. Loser66
    • one year ago
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    the last one.

  11. Loser66
    • one year ago
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    now replace all f'(1) =?

  12. Loser66
    • one year ago
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    f(1) =??

  13. anonymous
    • one year ago
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    h'(x)= 2?

  14. anonymous
    • one year ago
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    correction h'(1) = 2

  15. Loser66
    • one year ago
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    nope

  16. anonymous
    • one year ago
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    damn okay what'd i do wrong h'(x) = g"(3) * 2

  17. anonymous
    • one year ago
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    only one prime on the g ^^

  18. Loser66
    • one year ago
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    =??

  19. anonymous
    • one year ago
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    18 damn okay i see what i did wrong

  20. Loser66
    • one year ago
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    ok

  21. anonymous
    • one year ago
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    thank you very much

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